3 years ago

Calculate the percent of lead in Pb (Co3)2

1 answer:

7 0

We will take that molar mass of Pb(CO3)2 represents the total mass of all particles in this compound, ie it has value 100%.

M(Pb(CO3)2) = Ar(Pb) + 2xAr(C) + 6xAr(O) = 207.2 + 2x12 + 6x16= 327.2 g/mol

M(Pb) = 207.2 g/mol

From the date above we can set the following ratio:

M(Pb(CO3)2) : M(Pb) = 100% : x

327.2 : 207.2 = 100 :x

x = 63.33% of Pb there is in <span>Pb(Co3)2</span>

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