Answer:
259.497 mg, 58.84%
Explanation:
BaSO₄ → Ba²⁺ + SO₄²⁻
to calculate the mole of BaSO₄
mole BaSO₄ = mass given / molar mass = 403 mg / 233.38 g/mol = 1.7268 mol
comparing the mole ratio
1.7268 mol of BaSO₄ yields 1.7268 mol of Ba²⁺
403 mg BaSO₄ yields ( 1.7268 × 137.327 ) where 137.327 is the molar mass of Barium mol of Ba²⁺
441 mg BaSO₄ will yield ( 1.7268 × 137.327 × 441 mg ) / 403 mg = 259 .497 mg
mas percentage of the Barium compound = 259 .497 mg / 441 mg × 100 = 58.84%
Answer:
Option (3) 334J.
Explanation:
The following data were obtained from the question:
Mass (m) = 1g
Heat of fusion (ΔHf) = 334J/g
Heat (Q) =?
The heat released can be obtained as follow:
Q = m·ΔHf
Q = 1 x 334
Q = 334J.
Therefore, the heat released when 1g is converted to ice is 334J.
Answer:
HCOOH, H₃O⁺, and HCOO⁻
Explanation:
HCOOH is the major solute.
However, HCOOH is a weak acid. It dissociates slightly in aqueous solution.
HCOOH + H₂O ⇌ HCOO⁻ + H₃O⁺
Thus, two other solute particles are HCOO⁻ and H₃O⁺.
