Q = mCpΔT
Cp = 2.22 J/g°C
m = 150 g
ΔT = T(final) - T(initial) = -15°C - (-30°C) = +15°C
q = (150 g)(2.22 J/g°C)(15°C) = 4,995 J
solid : the molecules are tightly packed
liquid : the molecules have some space in them
gas : molecules can freely move around
Balance the equation: 2Na + S --> Na2S
Using the given amount of the reactants in the reaction, calculate the amount of the product:
45.3g Na x (1 mol/22.99 g)= 1.97 mol of Na
105f S x (1 mol/ 32.06g) = 3.28 mol of S
The limiting reactant would be Na:
<span>1.97 mol Na x (1 mol Na2S/ 2 mol Na) x (78.04g/mol) = 76.87g of Na2S produced</span>
