Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
int A[3][3],B[3][3],res[3][3],i,j;
srand(time(0));//for seed.
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
int val=rand()%100+1;//generating random values in range 1 to 100.
int val2=rand()%100+1;
A[i][j]=val;
B[i][j]=val2;
}
cout<<endl;
}
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
res[i][j]=0.5*A[i][j]+3*B[i][j];//storing the result in matrix res.
}
}
cout<<"Matrix A is"<<endl;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
cout<<A[i][j]<<" ";//printing matrix A..
}
cout<<endl;
}
cout<<"Matrix B is"<<endl;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
cout<<B[i][j]<<" ";//printing matrix B..
}
cout<<endl;
}
cout<<"The result is"<<endl;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
cout<<res[i][j]<<" ";//printing the result..
}
cout<<endl;
}
return 0;
}
Output:-
Matrix A is
13 95 83
88 7 14
24 22 100
Matrix B is
11 13 95
48 35 20
68 100 18
The result is
39.5 86.5 326.5
188 108.5 67
216 311 104
Explanation:
I have created 2 matrices A and B and storing random numbers int the matrices A and B.Then after that storing the result in res matrix of type double to store decimal values also.Then printing the res matrix.
Answer: True
Explanation:
Yes, the given statement is true that a DFA is equivalent to NFA in terms of power. For any type of NFA we can easily build an equal DFA so, the NFA are not much powerful as compared to DFA. Both NFA and DFA are characterized by a similar type of class.
DFA is a special case of NFA and They both defined in the same class of language. Each condition in the DFA get summarized by all the condition that the NFA has itself.
The correct answer is D. All of the above. Each of these extensions are able to execute files depending on what type of information the file contains.
