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Serhud [2]
3 years ago
6

What elements are mental and nonmental? Zn, Ne, Mg, Fe, Cl

Chemistry
2 answers:
konstantin123 [22]3 years ago
8 0

Zn (Zinc) is metal

Ne (Neon) is nonmetal

Mg (Magnesium) is metal

Fe (Iron) is metal

Cl (Chlorine) is nonmetal

Romashka [77]3 years ago
5 0

Answer:

Zn is metal, Ne is nonmetal, Mg is metal, Fe is metal, Cl is nonmetal

Explanation:

This is the answer because i always have a element table next to me because it is a specific poster in my room.

You might be interested in
Which is a proper description of chemical equilibrium?
serg [7]
D) because both reactions are occurring at the same rate. They are not equal but their concentrations are constant.
3 0
3 years ago
How many moles are in 8.32 x 1024 molecules of CO2.
Andrews [41]

Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.32 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 13.820598...

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

6 0
3 years ago
Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat
Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

4 0
3 years ago
2C₂H6 + 702 —&gt;4C02 + 6H₂O
navik [9.2K]

Answer:

975.56×10²³ molecules

Explanation:

Given data:

Number of molecules of C₂H₆ = 4.88×10²⁵

Number of molecules of CO₂ produced  =  ?

Solution:

Chemical equation:

2C₂H₆  + 7O₂     →      4CO₂ + 6H₂O

Number of moles of C₂H₆:

1 mole = 6.022×10²³ molecules

4.88×10²⁵  molecules×1mol/6.022×10²³ molecules

0.81×10² mol

81 mol

Now we will compare the moles of C₂H₆ with CO₂.

                     C₂H₆          :             CO₂

                          2           :               4

                           81         :           4/2×81 = 162 mol

Number of molecules of CO₂:

1 mole = 6.022×10²³ molecules

162 mol ×6.022×10²³ molecules / 1 mol

975.56×10²³ molecules

8 0
3 years ago
Does anyone know how to do this???
Bond [772]
Simply look at the periodic table and fill in what you know based on the table

The number of protons = atomic number
The number of electrons, Which is the same as the atomic number for atoms.

The number of valence electrons that is given by the group that the element is in, the top number of each column in the periodic table.







8 0
3 years ago
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