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Sveta_85 [38]
3 years ago
6

Two substances A and B react with each other in such a way that one-half of A remains after 25 min and one-fourth of A remains a

fter 50 min. Doubling the concentration of B while keeping the concentration of A fixed doubles the rate of the reaction. This reaction is
a. first-order in both A and B.
b. second-order in A and first-order in B.
c. zero-order in both A and B.
d. first-order in A and second-order in B.
e. second-order in both A and B.
Chemistry
1 answer:
juin [17]3 years ago
3 0

Answer:

a. first-order in both A and B.

Explanation:

In order to determine the kinetics of reaction let us consider the given data

a) Doubling the concentration of B while keeping the concentration of A fixed doubles the rate of the reaction. : it means the reaction is first order reaction with respect to reactant B.

b) The half life is the time required to complete the reaction by half way.

As with time one half of A remains and after equal time one fourth of A remains it means again the order of reaction is first with respect to A also.

There is no effect on the half life if we are decreasing the initial concentration of A also.

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When rocks grind and squeeze past each other,___metamorphism occur.
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Answer:

Dynamic

Explanation:

When rocks grind and squeeze past each other, dynamic metamorphism can occur.

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What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
3 years ago
How many ligaments in e kne
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Medial collateral ligament, which runs along inside of the knee.
Lateral collateral ligament, which runs along the outside of the knee.
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2 years ago
Classify water as proton donor or proton acceptor with reactions???
olasank [31]

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3 years ago
After substantial heating, 6.25 g of iron produced 18.00 g of a compound with chlorine. The empirical formula is:
babunello [35]

Answer:

Option A. FeCl3

Explanation:

The following data were obtained from the question:

Mass of iron (Fe) = 6.25g

Mass of the compound formed = 18g

From the question, we were told that the compound formed contains chlorine. Therefore the mass of chlorine is obtained as follow

Mass of chlorine (Cl) = Mass of compound formed – Mass of iron.

Mass of chlorine (Cl) = 18 – 6.25

Mass of chlorine (Cl) = 11.75g

The compound therefore contains:

Iron (Fe) = 6.25g

Chlorine (Cl) = 11.75g

The empirical formula for the compound can be obtained by doing the following:

Step 1:

Divide by their molar mass

Fe = 6.25/56 = 0.112

Cl = 11.75/35.5 = 0.331

Step 2:

Divide by the smallest

Fe = 0.112/0.112 = 1

Cl = 0.331/0.112 = 3

The empirical formula for the compound is FeCl3

3 0
3 years ago
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