Since the heat of combustion of butane is higher than that of propane, butane will produce more heat per gram when burned compared to propane.
The heat of combustion of a compound refers to the heat evolved when one mole of the compound is burnt under standard conditions. This heat of combustion increases from methane upwards.
Since the heat of combustion of alkanes increases according to increasing molar mass, butane will produce more heat per gram when burned compared to propane.
Learn more about heat of combustion: brainly.com/question/25312146
HEY DEAR..
<u>CHARGE</u><u> </u><u>AND</u><u> </u><u>MASS</u><u> </u><u>OF</u><u> </u><u>THE</u><u> </u><u>THREE</u><u> </u><u>SUBATOMIC</u><u> </u><u>PA</u><u>R</u><u>TICLES</u><u>.</u>
<h3>
1》Electron</h3>
(-) charge
1/1840 times of mass of hydrogen.
<h3>
2》proton</h3>
(+) charge
mass is 1.607×10^-27
<h3>
3》Nutron</h3>
it has no charge.
it mass is equal to the mass of proton.
HOPE ITS HELPFULL
Includes over 100 elements
the periodic table is written in almost all languages, there are not only natural elemnts, and it is ilogical only 66 elemnts
The process of formation of a reddish brown layer on an iron metal due to contact with air and water is known as corrosion.
Answer:
31.59 kpa
Explanation:
The variables in this problem are temperature and pressure. Both variables are related by the gay lusaacs law.
Gay-Lussac's Law: The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that as the pressure increases so does the temperature.
From the law, we have;
P1/P2 = T1/T2
From the problem;
P1 = Intial pressure = 30 kpa
P2 = Final pressure = x
T1 = Initial temperature = 10 + 273 = 283K (Upon converting to kelvin temperature)
T2 = Final temperature = 25 + 273 = 298K (Upon converting to kelvin temperature)
Substituting into the equation, we have;
30 / P2 = 283 / 298
Upon cross multiplication, we have;
P2 = (298 * 30 ) / 283
P2 = 31.59 kpa