Based on this equation: 2AL + 3CuCl2 -> 2AlCl3 + Cu ... how many grams of copper(II) chloride dihydrate would be required to

Question

Rasek [7]

3 years ago

8

Based on this equation: 2AL + 3CuCl2 -> 2AlCl3 + Cu ... how many grams of copper(II) chloride dihydrate would be required to

react completely with 1.20g of aluminum metal?

Chemistry

1 answer:

PolarNik [594] · Answer 1 · 2022-04-20T14:09:12+03:00

PolarNik [594]3 years ago

6 0

2Al + 3CuCl2 ➡ 2AlCl3 + 3Cu. Moles of Al = 1.2/27 = 0.045 moles 2 moles of Al reacts with 3 moles of CuCl2. Therefore, 1 mole of CuCl2 reacts with =2/3 x moles of Al = 2/3 x 0.045 = 0.03 moles.