Aidan has 6 (different) bulls and 10 (different) horses living at his animal sanctuary. He needs to place them in a line of 16 p
1 answer:
Answer: 5225472000
Step-by-step explanation:
Given : The number of bulls = 6
The number of horses = 10
Since Aidan needs to place them in a line of 16 paddocks, and the bulls cannot be placed in adjacent paddocks .
Also there are two ways to arrange the group pf bulls and horses.
Then , the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks will be :_
Hence, the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks =5225472000
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Answer:
m∠A = 30°
m∠B = 80°
m∠C = 70°
Step-by-step explanation:
By applying cosine rule in the given triangle,
b² = a² + c² - 2ac[cos(∠B)]
From the given triangle,
a = 14 m
b = 28 m
c = 24 m
(28)² = (14)² + (24)² - 2(14)(24)cos(B)
784 = 196 + 576 - 672cos(∠B)
cos(∠B) = 0.1786
∠B =
∠B = 79.71°
∠B = 80°
By applying sine rule in the given triangle,
sinA = 0.491958
A = 29.47°
A ≈ 30°
By applying triangle sum theorem,
m∠A + m∠B + m∠C = 180°
30° + 80° + m∠C = 180°
m∠C = 70°
I would have each block be 1/6 of a yard
You could technically have any value you want, but for me 1/6 is easiest because 1/2 and 1/3 will scale up to this like so
1/2 = (1/2)*(3/3) = 3/6
1/3 = (1/3)*(2/2) = 2/6
The diagram below might help if you're still stuck on why I picked 1/6.
