I believe the solution is a basic solution.
Good luck!
First, divide the given mass of lead (ii) chloride by the molar mass of the compound. The molar mass is equal to 278.1 g/mol.
n = m/M
where n is the number of moles, m is the given mass, and M is the molar mass. Substituting the known values,
n = 473.7 g / 278.1 g/mol
n = 1.7 mols
Then, it is to be remember that as per Avogadro, every mol of a substance contains 6.022 x 10^23 formula units.
N = (1.7 mols)(6.022 x 10^23 formula units/mol)
N = 1.02 x 10^24 formula units
Answer: 1.02 x 10^24 formula units
The number of mole of lithium, Li needed for the reaction is 3.2 moles (Option D)
<h3>Balanced equation </h3>
4Li + N₂(g) → 2Li₂N
From the balanced equation above,
2 moles of Li₂N were obtained from 4 moles of Li
<h3>How to determine the mole of lithium needed </h3>
From the balanced equation above,
2 moles of Li₂N were obtained from 4 moles of Li
Therefore,
1.6 moles of Li₂N will be obtained from = (1.6 × 4) / 2 = 3.2 moles of Li
Thus, 3.2 moles of Li are needed for the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
No because they have their full octet. They are full and don't need to bond with any other atoms. The full atoms that are happy are the noble gases.
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