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vodomira [7]
3 years ago
14

The attraction or repulsion of two objects is called blank force what is the blank

Mathematics
1 answer:
Crazy boy [7]3 years ago
3 0
I believe it would be magnetism.
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4(2x - 1) = 3x + 6 Solve for x. Show steps with sentences supporting each step.
mr Goodwill [35]

Answer:

x = 2

Step-by-step explanation:

4(2x - 1) = 3x + 6

Simplify

8x - 4 = 3x + 6

Subtract 3x from both sides

8x - 3x - 4 = 3x - 3x + 6

5x - 4 = 6

Add 4 to both sides

5x - 4 + 4 = 6 + 4

5x = 10

Divide both sides by 5

5x/5 = 10/5

x = 2

5 0
2 years ago
Read 2 more answers
Simplify 4^2 * 4^8= A.)4^16 B.)4^10 C.)16^16 D.)16^10 please help me i need this asap.
SVEN [57.7K]

Answer:

4^{10}

Step-by-step explanation:

Complete the exponents first.

4*4=16

4*4*4*4*4*4*4*4=65536

65536 *16= 1048576

The answer is 4^{10}

You can also find this if you add the exponents.

6 0
2 years ago
PLEASE HELP!!-What two rotations would provide the following images.
GREYUIT [131]
Reflection and rotation
3 0
3 years ago
Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance
kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

C^{2}=A^{2}+B^{2}-2ABcos \gamma

so we can solve the formula for C so we get:

C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}

and now we can substitute the values we know:

C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}

C=\sqrt{16+64-32\sqrt{2}}

C=\sqrt{80-32\sqrt{2}} mph

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0
3 years ago
Solve the following sysyem of equations by the substitution method.  5x+y=8<br> 3×+y=8
meriva
5x+y=8\\&#10;3x+y=8\\\\&#10;y=-5x+8\\&#10;3x+y=8\\\\&#10;3x-5x+8=8\\&#10;-2x=0\\&#10;x=0\\\\&#10;y=-5\cdot0+8\\&#10;y=8\\\\&#10;\boxed{(x,y)=(0,8)}
6 0
2 years ago
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