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atroni [7]
3 years ago
5

Solve for x. X = 12 4

Mathematics
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

Step-by-step explanation:

x = 8

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3 0
3 years ago
I don't know to find the answer to 8. Can someone explain to me?
lapo4ka [179]
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.

A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'

B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)

C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)

D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n

_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.

The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
7 0
3 years ago
which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f
Alecsey [184]

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

\frac{3}{4}+m=-\frac{7}{4}

We solve for m to obtain:

m=-\frac{7}{4}-\frac{3}{4}=-2.5

We also solve the remaining equations to see which ones give the same result.

A: m=\frac{10}{4} =2.5

B:m=-\frac{10}{4} =-2.5

C:m=-\frac{5}{2} =-2.5

D: \frac{11}{4}+m=-\frac{1}{4}

m=-\frac{1}{4}-\frac{11}{4}=-3

E: -\frac{5}{4}+m=-\frac{15}{4}

m=-\frac{15}{4}+\frac{5}{4}=-2.5

F: m+2=-0.5

m=-0.5-2=-2.5

The equivalent equations are; B,C,E, and F.

3 0
3 years ago
Read 2 more answers
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