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4 years ago

Despite a very strong wind, a tennis player

Physics

1 answer:

Gnoma [55]4 years ago

6 0

Answer:

Option 5. 1 and 3

Solution:

The only forces acting on the tennis ball after it has left contact with the racquet and the instant before it touches the ground are the force of gravity in the downward direction and the force by the air exerted on the ball.

The ball after it left follows the path of trajectory and as it moves forward in the horizontal direction the force of the air acts on it.

In the whole projectile motion of the ball, the acceleration due to gravity acts on the ball thus the force of gravity acts on the ball in the downward direction before it hits the ground.

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Which of Earths layers is made up of liquid metal

wolverine [178]

The outer core is made out of molten lava also known as liquid metal because of all the iron and other metals in it

7 0

3 years ago

A naked, male corpse was found at 8AM on Tuesday, July 9.The air temperature wasalready 26.7˚C (81˚F). The body exhibited some s

Slav-nsk [51]

Answer:

x = 9.87 hours ago.

Further explanation is present below.

Explanation:

Data given:

Air Temperature = 26.7°C (81°F)

Body temperature = 34.4°C (93.9°F)

We are given that, Livor mortis was absent. Secondly, The body exhibited some stiffness in the face and eyelids.

So, it can be concluded that, body must have died recently, as Livor mortis was absent plus the presence of stiffness in the face and eyelids. Furthermore,

The normal body temperature = 37°C

Body temperature in our case = 34.4° C

Difference = 37 -34.4 = 2.6°C

And Air temperature = 26.7°C

Which is a very low difference, in addition, it has not acquired the air temperature so, all this evidence certifies that body died recently.

Now, we have to calculate, how recently it died.

Formula:

0.78 . x = difference of body temperature and air temperature

Where, x = number of hours = time required,

0.78 . x = (34.4 - 26.7)

0.78 . x = 7.7

x = 7.7/0.78

x = 9.87 hours ago.

It means that, naked male corpse was died 9.87 hours ago.

Now, we are asked to find out clothing on the body had made a difference or not.

So, Yes it would definitely make a difference. As body would have more warmer than being naked. and it would result in a calculation of a different time of death. (body temperature would have > 34.4°C)

3 0

3 years ago

What would be the average fixed cost per unit at an activity level of 5,200 units? assume that this level of activity is within

Vitek1552 [10]

The average fixed cost per unit at an activity level of 5,200 units is $6.00.

<h3>What is the average fixed cost?</h3>

The average fixed cost (AFC) is fixed cost that does not change with the change in the number of goods and services produced by a company. To put it in a nutshell, average fixed cost (AFC) is the fixed cost per unit and is calculated by dividing the total fixed cost by output level.

Since no cost is fixed for a long time, average fixed cost is only for a short run. When units of production increase, the average fixed cost per unit decreases. Similarly, when the business produces less units, average cost increases per unit.

However, only one unit, mostly capital, is fixed. Examples of average fixed cost are the salaries of permanent employees, mortgage payment on machinery and plant, rent, more.

Average Fixed Cost Formula:

AFC = Total fixed cost/Output (Q)

To know more about plant visit: brainly.com/question/22167412

#SPJ4

4 0

2 years ago

The greater the force exerted by the engine of a car over a set distance, the greater the change in ?

aleksandrvk [35]

The greater the change in velocity, or speed.

8 0

4 years ago

"If the object has a speed of" -2.5 m/s at x = 0m, find its speed at x = 5.00 m and its speed at x = 15.0 m.

frez [133]

Answer:

Hello your question has some missing parts attached below is the missing part

A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

answer : speed at x = 5 m = 3.35 m/s

speed at x = 15m = 5.12 m/s

Explanation:

initial speed( x = 0 ) = 2.5 m/s

speed at x = 5.00 m = ?

speed at x = 15 m = ?

Determine speed at x = 5 m

First we will apply the expression for work-energy theorem

w = $\frac{1}{2} m(v^2 - v_{0}^2 )$ ----- ( 1 )

where : w = 7.50J, $v_{0}$ = 2.5m/s , m = 3.0 kg ( in the expression of work )

input values into equation 1

7.50 = 1/2 (3 ) ( v^2 - 2.5^2 )

7.50 = 3/2 ( v^2 - 6.25 )

5 j/kg = v^2 - 6.25

∴ v = √11.25 = 3.35 m/s

Determine speed at X = 15

first we will determine the work done form x = 5 to x = 15

W = 7.5J + 15J + 7.5J = 30J, $v_{0}$ = 2.5m/s , m = 3.0 kg

w = $\frac{1}{2} m(v^2 - v_{0}^2 )$ --- ( 2 )

equation2 becomes

30J = 1/2 ( 3 ) ( v^2 - 6.25 )

30J = 3/2 ( V^2 - 6.25 )

20 J/kg = v^2 - 6.25

v = √26.25 = 5.12 m/s

5 0

3 years ago