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docker41 [41]
2 years ago
9

If you are

Physics
1 answer:
zysi [14]2 years ago
7 0

Answer:

yes it doesn't matter

Explanation:

it doesn't matter because troughs and crests are the same and either can be used

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Un niño de 25 kg corre por un jardín con una velocidad de 2.5 m/s de forma que su trayectoria es tangente al borde de un carruse
Schach [20]

Answer:

La velocidad angular del niño y del carrusel cuando se mueven juntos es 0.208 radianes por segundo.

Explanation:

Asumamos que tanto el niño como el carrusel no tienen carga externa aplicada sobre aquellos, de modo que se puede aplicar el Principio de Conservación de la Cantidad de Movimiento Angular:

m\cdot v \cdot R = (m\cdot R^{2}+I)\cdot \omega (1)

Donde:

m - Masa del niño, medida en kilogramos.

v - Velocidad lineal inicial del niño, medida en metros por segundo.

R - Radio máximo del carrusel, medida en metros.

I - Momento de inercia del carrusel, medida en kilogramo-metros cuadrados.

\omega - Velocidad angular final del sistema niño-carrusel, medida en radianes por segundo.

Si sabemos que m = 25\,kg, v = 2.5\,\frac{m}{s}, R = 2\,m y I = 500\,kg\cdot m^{2}, tenemos que la velocidad angular final es:

\omega = \frac{m\cdot v\cdot R}{m\cdot R^{2}+I}

\omega = \frac{(25\,kg)\cdot \left(2.5\,\frac{m}{s} \right)\cdot (2\,m)}{(25\,kg)\cdot (2\,m)^{2}+500\,kg\cdot m^{2}}

\omega = 0.208\,\frac{rad}{s}

La velocidad angular del niño y del carrusel cuando se mueven juntos es 0.208 radianes por segundo.

4 0
3 years ago
Who's wrong? I think the correct numbers would be 17 and 18, not 18 and 19.
denpristay [2]
The correct answer is: 17 and 18 <-----

Hope i helped!:)
5 0
3 years ago
Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on co
krok68 [10]

Gymnasts often practice on foam floors, which increase the collision time when a gymnast falls. What effect does this have on collisions

The effect of the gymnast on the collision will increase. An elastic collision is when two bodies collide and separates after collision conserving the total kinetic energy before and after collision.

8 0
3 years ago
A 35 g block of ice is cooled to −83 ◦C. It is added to 565 g of water in an 87 g copper calorimeter at a temperature of 22◦C. F
Tcecarenko [31]

Answer:

Explanation:

Heat gained by ice in warming up to 0⁰C = .035 x 2090 x (83-0)= 6071.45 J

heat used up by ice to melt at 0⁰C = .035 x 3.33 x 10⁵ J = 11655 J

Heat used up in warming up water to t⁰C = .035 x 4186 x t = 146.51 t

heat released by warm water to cool from 22⁰C to t = .565 x 4186 x ( 22 - t )

=52032 -2365.1 t

heat released by copper calorimeter  to cool from 22⁰C to t =  .087 x 387 x ( 22 - t ) = 740.72 - 33.7 t

total heat released = 52032 -2365.1 t  + 740.72 - 33.7 t

= 52772.72 - 2398.8 t

Heat lost = heat gained

52772.72 J- 2398.8 t  = 6071.45 J + 11655 J + 146.51 t

2545.31 t = 35046.27

t = 13.8°C.

7 0
3 years ago
A 6-column table with 1 row. The first column labeled Number of Washers has entry 2. The second column labeled initial velocity
BigorU [14]

Answer:

.33

.17

Explanation:

I just did the assignment

6 0
3 years ago
Read 2 more answers
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