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balandron [24]
3 years ago
8

A circuit element maintains a constant resistance. If the current through the circuit element is doubled, what is the effect on

the power dissipated by the circuit element
Physics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

<h3>This shows that the power dissipated by the circuit element is four times its original power if the current is doubled.</h3>

Explanation:

The formula for calculating the power expended in a circuit is P =  I²R... 1

i is the current (in amperes)

R is the resistance (in ohms)

If  a circuit element maintains a constant resistance and the current through the circuit element is doubled, then new current I₂ = 2I

New power dissipated P₂ = (I₂)²R

P₂ = (2I)²R

P₂ = 4I²R ... 2

Dividing equation 2 by 1 will give;

P₂/P = 4I²R/I²R

P₂/P = 4

P₂ = 4P

This shows that the power dissipated by the circuit element is four times its original power if the current is doubled.

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defon

The force of the racket affects the ball's motion because it changes the momentum of the ball.

<h3>Impulse received by the ball</h3>

The impulse received by the ball through the racket affects the motion because it changes the momentum of the ball.

The ball which is initially at rest, will gain momentum after been hit with the racket.

J = ΔP = Ft

where;

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Thus, the force of the racket affects the ball's motion because it changes the momentum of the ball.

Learn more about impulse here: brainly.com/question/25700778

4 0
2 years ago
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Virty [35]
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4 0
3 years ago
None of these make sense someone help
vfiekz [6]

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6 0
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dezoksy [38]

Answer:

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