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3 years ago

What type of rock is calcite?

Chemistry

2 answers:

user100 [1]3 years ago

7 0

Calcite comes from limestones and limestones are sedimentary.

So calcate is sedimentary rock

Damm [24]3 years ago

3 0

The answer is C) Metamorphic

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Which of the following bonds is the strongest? H-H C-CI C=O N-N

Arisa [49]

Double bonds are stronger than single bonds. So C=O.
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4 years ago

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A mixture of CO2 and Kr weighs 35.0 g and exerts a pressure of 0.708 atm in its container. Since Kr is expensive, you wish to re

ollegr [7]

Explanation:

Since, it is given that carbon dioxide is completely removed by absorption with NaOH. And, pressure inside the container is 0.250 atm.

For Kr = 0.250 atm and pressure $CO_{2}$ will be calculated as follows.

$CO_{2}$ = (0.708 - 0.250) atm

= 0.458 atm

Now, we will calculate the mole fraction as follows.

$CO_{2} = \frac{0.458}{0.708}$

= 0.646

Kr = $\frac{0.250}{0.708}$

= 0.353

Now, we will convert into gram fraction as follows.

$CO_{2} = 0.646 \times 44$

= 28.424

Kr = $0.353 \times 83.78$

= 29.57

Therefore, total mass is calculated as follows.

Total mass = (28.424 + 29.57)

= 57.994

Hence, the percentage of $CO_{2}$ and Kr are calculated as follows.

$CO_{2} = \frac{28.424}{57.99} \times 100$

= 49%

Kr = $\frac{29.57}{57.99} \times 100$

= 51%

Hence, amount of $CO_{2}$ and Kr present i mixture is as follows.

$CO_{2}$ in mixture = $35 \times 0.49$

= 17.15 g

Kr = $35 \times 0.51$

= 17.85 g

Thus, we can conclude that 17.15 g of $CO_{2}$ is originally present and 17.85 g of Kr is recovered.

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3 years ago

The function of this organelle is to create energy (ATP) through the process of cellular respiration.

dedylja [7]

Answer:

Explanation:

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3 years ago

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lesantik [10]

Answer:

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3 years ago

Can you help me understand this ? I completely dont understand it . i know the tire will burst.

icang [17]

Answer:

There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.

1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol

2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa

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Explanation:

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4 years ago

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