Answer:
i hope it helps
Explanation:
This reaction involve an acid (HCl) reacting with a base (NaOH), producing a salt (NaCl) and water. Therefore it's a neutralization reaction.
Answer:
NaNO₃
Explanation:
A precipitate is a compound or a salt formed from a precipitation reaction and does not dissolve in water and therefore will exist in solid state.
From the choices given precipitation reaction will occur between;
- Fe(NO₃)₃(aq) + 3NaOH(aq) → Fe(OH)₃(s) + 3NaNO₃(aq)
- Cu(NO₃)₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaNO₃(aq)
- FeSO₄(aq) + 2NaOH(aq) → Fe(OH)₂(s) + Na₂SO₄(aq)
Fe(OH)₃, Cu(OH)₂, and Fe(OH)₂ are precipitates.
From the rules of solubility, hydroxides are insoluble except Ca(OH)₂ which is slightly soluble and hydroxides of ammonium and alkali metals.
Answer:
A-A and B-B attractive forces contains more energy than AB attractive forces
Explanation:
AA and BB are separated as solutes and solvents in themselves which is an endothermic reaction ΔH<0 while they are free to react to form the product AB that contains lesser amount of energy than the reactants AA and BB of which the excess energy is observed as increased temperature of the solution
ΔH<0 : Exothermic Reaction (negative), because the the products less energetic than reactants.
Dispersing the molecular bonds of the solute AA and the solvent BB solutions by themselves are generally endothermic reactions in as their cohesive forces are broken down to allow them mix, while allowing the free reaction of the molecules is an exothermic reaction as they form the solution component AB which is less energetic accompanied by excess energy as that is observed in heat of the reaction
Answer:
Ionic
Explanation:
Lithium is an alkali metal and form an ionic bond by donating an electron.
Fluorine is a halogen and forms ionic bonds by accepting an electron.
The electronegativity difference between lithium (0.98) and fluorine (3.98) is 3 Pauling units. Usually, when elements have a difference of 1.7 (or 2.0) Pauling units the bond is classified as ionic.
Hope this helps! If you have any more questions or need more explanation please leave a comment down below and I will reply ASAP. Good luck!
