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Stella [2.4K]
3 years ago
9

Heat in a substance is an example of ________ energy. A. phase B. kinetic C. potential D. evaporative

Chemistry
2 answers:
lisov135 [29]3 years ago
8 0
The correct answer that would best complete the given statement above is option B. Heat in a substance is an example of a kinetic energy. Kinetic energy is a kind of energy that is in motion. We can feel the kinetic energy of heat through their temperatures because heat is being transferred. 
Marina86 [1]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

When there will be flow of energy from one substance to another then it is defined as the heat.

Since, heat is responsible for the movement of particles of a substance. This means that more if the heat more will be the kinetic energy as kinetic energy is the energy obtained by particles of a substance due to their motion.

Also, kinetic energy is directly proportional to temperature.

                     K.E = \frac{3}{2}kT

So, more is the temperature of an object more will be heat transferred by it. Therefore, more will be its kinetic energy.

Thus, we can conclude that heat in a substance is an example of kinetic energy.

You might be interested in
When 33 g of CaO and 10 g of H2O react, how many grams of calcium hydroxide would you expect to be produced* Explain your answer
MrMuchimi

Answer:

41.44 g

Explanation:

First of all, we must put down the equation of the reaction;

CaO + H2O ----->Ca(OH)2

Number of moles of CaO = 33g/56 g/mol = 0.59 moles

Number of moles of H20 = 10g/18 g/mol = 0.56 moles

Since the reaction is in 1:1 mole ration, H2O is the limiting reactant

Hence;

mass of Ca(OH)2 produced = 0.56 moles * 74 g/mol = 41.44 g

7 0
3 years ago
Read 2 more answers
From the lists of available reagents select the one(s) you would use to in a preparation of acetophenone (phenyl methyl ketone)
VARVARA [1.3K]

Answer:

Step 1) hydrolysis using NaOH/H2O to form benzylalcohol

Step2) oxidation to Carboxylic acid using KMnO4 followed by decarboxylation to form benzene

3) friedel craft acylation using CH3COCl/AlCl3

Explanation:

The above 3 steps will yield acetophenone from methylbenzoate

3 0
3 years ago
Let’s say that you have a solvatochromic compound that appears red in a solvent. You dissolve the compound in another solvent an
EastWind [94]

Answer:

Hypsochromic compound, More polar solvent

Explanation:

Hypsochromic shift refers to the shift of solution colour to blue side of the visible spectrum (blueshift) with increasing polarity of the solvent. In our case, the solution changes to orange colour from red when solvent is changed. This means that the emission spectrum of the solution underwent blueshift. (As orange colour is on the 'blue' side for red colour.) So this is a hypsochromic shift, and the new solvent is more polar that the previous one, as it caused hypsochromic shift.

7 0
3 years ago
Can you look at the picture Look at the picture ASAP and help please?
Murrr4er [49]

Answer:

Volume of the reaction vessel is increased - shift to the left

The reaction is cooled down - shift to the right

H2 is added to the system - shift to the right

The pressure of the system is decreased - shift to the left

A catalyst is added to the system - no change

Water is removed from the system - shift to the right

Explanation:

When a constraint such as a change in temperature, pressure or volume is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.

When the volume of a reaction system is increased, the equilibrium position shifts in the direction in which there is the highest total volume. This is the left hand side.

Since the reaction is exothermic (heat is given out) when the reaction is cooled down, the forward reaction is favoured.

Adding of reactants shifts the equilibrium position to the right hand side hence when H2 is added, the equilibrium position shifts to the right.

Decreasing the pressure shifts the equilibrium position to the direction of higher total volume hence the equilibrium shifts to the left when pressure is decreased.

A catalyst has no effect on the equilibrium position. It increases the rate of forward and reverse reaction to the same extent hence the equilibrium position is unaffected.

Removal of water from the system increases the rate of forward reaction since a product is being removed from the reaction system.

7 0
3 years ago
Describe the process you used to build a model. What did you do first? second?
dimaraw [331]
First read the introduction.

Seconds look at the pictures how to build it.
3 0
3 years ago
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