Write an equation that shows the reaction between acetic acid (ch3cooh) and triethylamine (ch3ch2)3n. Draw all non-bonding lone
electron pairs and show the electron flow with curved arrows.
1 answer:
Due to the lone pair of electron present on nitrogen in ethylamine, it will behave as base and attack on the hydrogen of hydroxy group of acetic acid,
which is an acid and results in the formation of conjugate acid of triethyl amine and conjugate base of acetic acid.
The reaction between triethylamine and acetic acid is shown in the attached image.
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