The elements heavier than hydrogen and helium were produced inside stars.
During most of a star's lifetime, hydrogen nuclei fuse together to form helium nuclei.As the star runs out of hydrogen, other elements. Heavier elements than hydrogen and helium are form. Elements heavier than iron are formed in supernovas.
Answer:
Mesosphere
Stratosphere
Thermosphere
Troposphere
Exosphere
Explanation:
The exosphere refers to the farthest region of the atmosphere that gradually fades into space.
The troposphere is the lowest layer of atmosphere. It is the layer where weather changes occur.
The thermosphere is right above the mesosphere but just below the exosphere. It is the layer where photoionization/photodissociation of molecules occurs thereby creating ions. This largely owes to interaction of molecules in this layer with ultraviolet radiation.
The stratosphere is composed of gases. Prominent among them is ozone which serves as a blanket against the sun's ionizing radiation.
The mesosphere lies above the stratosphere but just below the thermosphere. Temperature decreases steadily with height in the mesosphere.
Answer:
60 g
Explanation:
The formula relating mass (<em>m</em>), heat (<em>q</em>), and temperature change (Δ<em>T</em>) is
<em>q = mC</em>Δ<em>T</em> Divide both sides by <em>C</em>Δ<em>T</em> and switch
<em>m</em> = <em>q</em>/(<em>C</em>Δ<em>T</em>)
<em>q</em> = 1260 J
<em>C</em> = the specific heat capacity of water = 4.184 J·K⁻¹g⁻¹
Δ<em>T</em> = <em>T</em>₂ - <em>T</em>₁ = 313 K – 308 K = 5 K
<em>m</em> = 1260/(4.184 × 5)
<em>m</em> = 1260/21
<em>m</em> = 60 g
Answer:
36.63 Torr
Explanation:
You need to use two expressions, one for pressure and the other with the relation of density and height of the column.
For the pressure:
P = h * d * g (1)
h is height.
d density
g gravity
The second expression put a relation between the densities and height of the column so:
d1/d2 = h1/h2 (2)
let 1 be the phthalate, and 2 the mercury.
Let's calculate first the relation of density:
d1/d2 = 13.53 / 1.046 = 12.93
Now with the first expression, we can calculate the pressure so:
P = hdg
We have two compounds so,
h1d1g = h2d2g ---> gravity cancels out
From here, we can solve for h2:
h2 = h1*(d1/d2)
replacing:
h2 = 459 / 12.53
h2 = 36.63 mm
1 mmHg is 1 torr, therefore the pressure of the gas in Torr would be 36.63 Torr
The time it takes for the boiling point increases.