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4 years ago

What is the electron configuration of Lithium

Chemistry

1 answer:

9966 [12]4 years ago

8 0

Answer:

[He] 2s1

Explanation:

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What is the mass of 6.02 x 1023 particles of rubidium carbonate

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Answer:

Explanation:

84.97

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3 years ago

Is Cu2O+C= Cu+CO2 a balanced equation

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4 years ago

How many joules are required to convert 16.5 g g of ice at 0.0 ∘C ∘ C to liquid water at 32.0 ∘C ∘ C ? The heat of fusion of wat

photoshop1234 [79]

Answer:

5511 J

Explanation:

Applying,

Q = Cm.................... Equation 1

Where Q = amount of heat required to convert ice, C = Heat of fusion of water, m = mass of ice

From the question,

Given: C = 334 J/g, m = 16.5 g

Substitute these values into equation 2

Q = 334(16.5)

Q = 5511 J

Hence, the amount of heat required is 5511 J

4 0

3 years ago

6. Write the ICE chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: S8 + 4 Cl24S2Cl2 After completing the chart

Marianna [84]

Answer:

ICE Table Figure

a. 67.37 g $S_2Cl_2$

b. 35.62 g $Cl_2$

c. 58.61 g $S_2Cl_2$

Explanation:

For the ICE table we have to keep in mind that we have 4 moles of $Cl_2$ and 1 mol of $S_8$ and the reactives are consumed, so for $Cl_2$ we will have -4X and for $S_8$ we will have -X. Follow the same logic we will have -4X for $S_2Cl_2$ .

a. Mass of the product

Molar mass of $S_8$ = 256.52 g/mol

Molar mass of $Cl_2$ =70.9 g/mol

Molar mass of $S_2Cl_2$ =135.03 g/mol

We have to find the limiting reagent in the reaction:

$S_8+4Cl_2->4S_2Cl_2$

$\frac{32}{256.52}=0.124molS_8$

$\frac{71}{70.9}=1 molCl_2$

Divide by the coefficients in the balanced reaction:

$\frac{0.124}{1}=0.124mol$

$\frac{1}{4}=0.25 mol$

The limiting reagent would be $S_8$

Now is posible to calculate the amount of $S_2Cl_2$ produced:

$0.124molS_8\frac{4molS_2Cl_2}{1 molS_8}\frac{135.03gS_2Cl_2}{1 molS_2Cl_2}=67.37gS_2Cl_2$

b. Mass in excess

$0.124molS_8\frac{4molCl_2}{1 molS_8}\frac{70.9gCl_2}{1 molCl_2}=35.38gCl_2$

$Excess\hspace{0.1cm}=\hspace{0.1cm}71gCl_2-35.38gCl_2=35.62 gCl_2$

C. 87%Yield

$67.37gS_2Cl_2\frac{87}{100}=58.61gS_2Cl_2$

5 0

4 years ago

NEED HELP ASAP!!! Please choose correctly!! Will mark brainliest thank you!!!

almond37 [142]

You will have a excess gas

4 0

4 years ago