Question

What is the [OH-] in a solution that has a [H3O+] = 1.0 x 10-6 M?

Answer 1

Answer:

explanation

$kw = 1 \times {10}^{ - 14}$

$oh = {?}$

$h3o = 1.0 \times 10 {}^{ - 6}$

$formula$

$kw = h3o \times oh$

$insert \: values$

$1.0 \times 10 {}^{ - 14} = 1.0 \times {10}^{ - 6} \times oh$

$\frac{1.0 \times 10 {}^{ - 14} }{ 1.0 \times 10 {}^{ - 6} } = oh$

$1 \times {10}^{ - 8}$