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Naddika [18.5K]
4 years ago
15

A person has been exposed to a particular antigen and now experiences a repeat exposure. What stimulates a quicker immune respon

se?a) Memory T cellsb) immunityc) antibodiesd) macrophages
Physics
1 answer:
Anit [1.1K]4 years ago
7 0

Answer:

a. Memory T cells

Explanation:

Memory T cells are actually the antigen-specific T cells that remain long-term after an infection has been eliminated. These memory T cells are quickly converted into large numbers of effector T cells upon reexposure to the specific invading antigen, thus providing a rapid response to past infection that has been experienced before

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The acceleration due to gravity of the earth is 9.81 m/s2 and the acceleration due to gravity of the moon is 1.625 m/s2. If your
Viktor [21]

Answer:

686 N

113.75 N

Explanation:

On Earth:

W= mg

= 70 x 9.8

= 686 N

On Moon:

W= mg

= 70 x 1.625

= 113.75 N

3 0
3 years ago
Q3. What is the minim value of refractive index?
Airida [17]

Answer:

Absolute refractive index is 1

Relative refractive index is lesser than 1.

Explanation:

6 0
3 years ago
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Every day Sharon worries about whether she turned off the stove. She can barely think of anything else. This is an example of a/
OLEGan [10]
I would like some more details if that's ok, like was there any answer choices?
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4 0
3 years ago
A type of light bulb is labeled having an average lifetime of 1000 hours. It’s reasonable to model the probability of failure of
SashulF [63]

Answer:

0.2592 \ or \ 25.92\%

Explanation:

The exponential density function is given as

f(t)=\left \{ {{0} \atop {ce^{ct}}} \right\\0,t

\mu=\frac{1}{c}\\c=\frac{1}{\mu}\\\\=\frac{1}{1000}=0.001\\\\f(t)=0.001e^{-0.001t}

To find probability that bulb fails with the first 300hrs, we integrate from o to 300:

P(0\leq X\leq 300)=\int\limits^{300}_0 {f(t)} \, dt\\\\=\int\limits^{300}_0 {0.001e^{-001t}} \, dt\\ =|-e^{-0.001t}|  \ 0\leq t\leq 300

P(0\leq X\leq 300)=-0.7408+1\\=0.2592

Hence probability of bulb failing within 300hrs is 25.92% or 0.2592

3 0
3 years ago
Blocks A and B are identical metal blocks. Initially block A is neutral, and block B has a net charge of 8.7 nC. Using insulatin
JulsSmile [24]

Explanation:

(a)   Since, it is given that the blocks are identical so distribution of charge will be uniform on both the blocks.

Hence, final charge on block A will be calculated as follows.

         Charge on block A = \frac{(8.7 + 0 nC}{2}

                                           = 4.35 nC

Therefore, final charge on the block A is 4.35 nC.

(b)  As it is given that the positive charge is coming on block A . This means that movement of electrons will be from A to B.

Thus, we can conclude that while the blocks were in contact with each other then electrons will flow from A to B.

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3 years ago
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