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3 years ago

10

Math question below image below

2 answers:

crimeas [40]3 years ago

7 0

Super easy, the answer in 10! ( :

enyata [817]3 years ago

3 0

Just add the x's its simple, answer is 10

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Evaluate the geometric series

Schach [20]

Your multiplying by -4 each time

-1x-4=4

4x-4=-16

-16x-4=64

3 0

3 years ago

Which of the following terms correctly describe the figure given below? Check all that apply

Evgesh-ka [11]

Answer:

one of the answers is E,F

Step-by-step explanation:

I know this becuase that is a pyramid right there it is an solid but no prims or anything else on there

3 0

3 years ago

ROOTS AND CUBES<br> Can someone please help me answer all 4 following?

Alex Ar [27]

NOTES:

squared (²) means multiply that number by itself 2 times
cubed (³) means multiply that number by itself 3 times
square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

$\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41$

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

$\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}$

$=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}$

$=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9$

$=(7 - 2)\times \dfrac{1}{5}+9$

$=5 \times \dfrac{1}{5}+ 9$

$= 1 + 9$

$= 10$

***************************************************************************************

8² = 8 · 8 = 64 11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27

$\sqrt{1600}=\sqrt{40\cdot 40}=40$ $\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4$

$\sqrt{144}=\sqrt{12\cdot 12}=12$ $\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20$

3 0

3 years ago

Solve the system of linear equations by elimination.<br> -3.x – 5y = -7<br> -4x + 5y = 14

julia-pushkina [17]

Answer:

(- 1, 2 )

Step-by-step explanation:

Given the 2 equations

- 3x - 5y = - 7 → (1)

- 4x + 5y = 14 → (2)

Add the 2 equations term by term to eliminate y , that is

- 7x + 0 = 7

- 7x = 7 ( divide both sides by - 7 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (1)

- 3(- 1) - 5y = - 7

3 - 5y = - 7 ( subtract 3 from both sides )

- 5y = - 10 ( divide both sides by - 5 )

y = 2

solution is (- 1, 2 )

8 0

3 years ago

Read 2 more answers

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

$-2(x-(-10))+5(y-7)+1(z-5)=0$

$-2(x+10)+5y-35+z-5=0$

$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

4 0

3 years ago