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2 years ago

6

Fix the error: Here’s why you should skip the skimp milk and go for whole milk instead.

2 answers:

Sveta_85 [38]2 years ago

8 0

Answer:

Here's why you should skip the skim milk and and go for whole milk instead.

Step-by-step explanation:

Dafna1 [17]2 years ago

6 0

Answer:

Here is why you should skip the skimp milk and go for whole milk.

Step-by-step explanation:

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A bag of coins contains 2 quarters, 5 dimes, 3 nickels, and 4 pennies. If 2 coins are randomly chosen from the bag, one after th

sineoko [7]

The two coins chosen have to be a quarter and a penny. That leaves you with three pennies. You originally had 14 coins. You took out two you now have 12.

<span>3/12 = 1/4 </span>

7 0

3 years ago

Read 2 more answers

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

A submarine 625 feet below sea level ascends (rises up) 575 feet before descending (submerging down) another 455 feet. Describe

blagie [28]

Answer:

505ft below the surface

Step-by-step explanation:

subtract 575 from 625 and then add 455 to get your final answer.

4 0

3 years ago

Solve each equation x+2y=1 and -x+y=2

Rudiy27

Answer:

x = -1, y = 1

Step-by-step explanation:

x + 2y = 1

Subtract 2y from both sides

x + 2y - 2y = 1 - 2y (simplify) -> x= 1 - 2y

----

-x + y = 2

Subtract y from both sides

-x + y - y + 2 - y (simplify) -> -x = 2 - y

Divide both sides by -1

$\frac{-x}{-1}$ = $\frac{2}{-1}$ - $\frac{y}{-1}$ (simplify) -> x = -2 + y

6 0

1 year ago

Is 60:45 and 4:3 are equivalent ratios<br>

WARRIOR [948]

Answer:

yes

Step-by-step explanation:

if we divide both terms of 60 and 45 by 15, we can simplify it to 4:3.

6 0

2 years ago