All categories

4 years ago

What force is exerted on a machine?

Physics

2 answers:

dedylja [7]4 years ago

8 0

input force :) k have a good day

Anna [14]4 years ago

7 0

lbs pounds . it puts pressure on everything

You might be interested in

. If the moon orbits Earth along the exact ecliptic (as the sun does): a. precession would not occur. b. days and nights would n

Ostrovityanka [42]

If the moon orbits Earth along the exact ecliptic a total lunar and solar eclipse would occur every month.

The answer is option C.

A solar eclipse happens when the Moon passes between the sun and Earth, casting a shadow on earth that either fully or partly blocks the sun's light in some areas. This most effective takes place every so often, due to the fact the Moon does not orbit inside the specific same plane because the solar and Earth do.

The moon's route crosses the ecliptic kind two times every month, and a solar eclipse takes place while the solar happens to be there at some point during the crossing. There's a terrific hazard of this approximately once each six months.

Learn more about the solar eclipse here: brainly.com/question/21576036

#SPJ4

4 0

2 years ago

We can determine the velocity of a wave when given the frequency and the (2 points)

xz_007 [3.2K]

We can determine the velocity of a wave when given the frequency and the wavelength

The velocity of a wave is eqiuvalent to its wavelength multiplied by its frequency

5 0

3 years ago

Read 2 more answers

Evaluate cosπ/11+cos3π/11+cos5π/11+cos7π/11+cos9π/11

alexandr402 [8]

Using a calculator, the answer will be 1/2 as a result of all the / and use of opposite πs that form 18 making a whole circle.

4 0

3 years ago

Read 2 more answers

Question 17 of 25

Scorpion4ik [409]

Answer:

The speed of the wave as it travelled through the brass bell is;

B. 4,700 m/s

Explanation:

The given parameters are;

The wavelength of the sound wave produced from the brass bell, $\lambda _{(air)}$ = 3.5 m

The wavelength of the wave in the brass bell, $\lambda _{(brass \ bell)}$ = 47 m

The frequency of the wave in the brass bell, f = 100 Hz

The given equation for wave speed, v = f × λ

Therefore, the speed of the wave as it travelled through the brass bell, $v _{(brass \ bell)}$ , is given as follows;

$v _{(brass \ bell)}$ = f × $\lambda _{(brass \ bell)}$ = 100 Hz × 47 m = 4,700 m/s

The speed of the wave as it travelled through the brass bell = $v _{(brass \ bell)}$ = 4,700 m/s

5 0

3 years ago

Read 2 more answers

A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial

Mashcka [7]

Answer: 0.076 m

Explanation:

Magnetic force= centripetal force;

F(B) = F(c) --------------------------(1)

Bqv= mv^2/R---------------------(2)

Where B= magnetic field,q= charge, = mass, R= radius of the circular path.

Radius of the circular path,R= mv/qB.

Mass of oxygen-16 is 2.66e−26kg, and they are singly charged = 18/16(mass ratio= 18:16)

18/16 × (2.26 × 10^ -26 kg)

= 2.99 × 10^26 kg

∆d=2r(18)-2r(16)-----------------(3)

r(18) is the radius of mass of oxygen-18,

r(16) is the radius of mass of oxygen-16.

From the question, v= 3.7×10^6 m/s, q= 1.6×10^-9 C.

From equation (2) above we have;

R= MV/qB------------------------(4)

This equation (4) is used in solving for the distance between the two.

Solving;∆d=2r(18)-2r(16)

∆d = 2[m(18) - m(16)] v/ qB

M(18)-m(16) =(2.99-2.66)× 10^-26:

qB= 1.6×10^-19×2 = 3.2×10^-19

= (2.99-2.66)× 10^-26/ 3.2× 10^-19

= 0.076 m

7 0

3 years ago