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Ivan
3 years ago
9

An 8kg soccer ball starts at rest and is kicked 31.5 meters until it reaches a final velocity of 21m/s in 3 seconds. Assuming th

at the soccer ball was kicked with a force of 56N (and ignoring any outside friction or air resistance forces), what is the power with which the soccer ball moved?
Physics
1 answer:
likoan [24]3 years ago
3 0

Answer:

The power with which the soccer ball moved is 588 W .

Explanation:

Given :

Mass of soccer ball , m = 8 kg .

Distance moved , d = 31.5 m .

Final velocity , v = 21 m/s .

Time taken , t = 3 s .

Force applied , F = 56 N .

We know , power is given by :

P=\dfrac{Work \ Done }{Time \ Taken }      ......( 1 )

Now , work done is given by :

W = Fd = 56\times 31.5\ J\\\\W=1764\ J

Now , putting value of P and t in equation 1 .

We get :

P=\dfrac{1764}{3}\ W\\\\P=588\ W

Therefore , this is the required solution .

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Yuki888 [10]

Answer:

speed wind  Vw = 54.04 km / h   θ = 87.9º

Explanation:

We have a speed vector composition exercise

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Let's use the Pythagorean theorem and trigonometry to compose the answer

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The speed direction is 87. 9th measure In the third quadrant of the X axis in the direction 90-87.9 = 2.1º  west from the south

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I hope this helps you:)

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