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3 years ago

15

If you quadruple the input of the function and the resulting output is one-fourth the original output,what may be true of the fu

nction?

2 answers:

Oksana_A [137]3 years ago

8 0

Answer:

The function is inversely proportional and more input results in less output.

IRINA_888 [86]3 years ago

4 0

<span>More input results in less output.The function is inversely proportional.

</span>

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Solve using substitution:<br> 2x - 3y = -1<br> y = x - 1

denis-greek [22]

<em>Answer:</em>

<em>x=4 y=3</em>

<em>Step-by-step explanation:</em>

<em>rewrite the equations- y=x-1 2x-3y=-1</em>

<em>solve y=x-1 for y</em>

<em>y=x-1</em>

<em>sub for x-1 for y in 2x-3y=-1</em>

<em>2x-3y=-1</em>

<em>2x-3(x-1)=-1</em>

<em>-x+3=-1</em>

<em>-x+3+-3=-1+-3</em>

<em>-x=-4</em>

<em>divide both sides by -4</em>

<em>x=4</em>

<em>sub 4 for x in y=x-1</em>

<em>y=x-1</em>

<em>y=4-1</em>

<em>y=3</em>

<em>WE ARE VENOM</em>

8 0

3 years ago

Which of the following is not a rigid motion

77julia77 [94]

Dilation is not a rigid motion.

7 0

3 years ago

Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id

Thepotemich [5.8K]

$\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

Explanation

$\frac{1}{a+bi}=c+di$

Step 1

multiplicate by the conjugate

$\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}$

notice that

$\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\ \end{gathered}$ $\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}$

I hope this helsp you

6 0

1 year ago

The population of the United States was about 280 million in 2000 and about 310 million in 2010. What was the annual rate of cha

JulsSmile [24]

To find the annual rate of chnge, we have to use the following formula

$\frac{P(2010)-P(2000)}{2010-2000}$

P(2010) represents the population in the year 2010 and P(2000) represents the population in the year 2000 .

Substituting the values, we will get

$\frac{310-280}{2010-2000} = \frac{30}{10} = 3 \ million \ per \ year$

8 0

3 years ago

What is the radius of a circle given by equation x^2 + y^2 - 2x + 8y - 47 = 0

Lera25 [3.4K]

X^2 + y^2 - 2x + 8y - 47 = 0
x^2 + y^2 - 2x + 8y = 47
(x^2 - 2x) + (y^2 + 8y) = 47
(x^2 - 2(1)x) + (y^2 + 2(4)y) = 47
(x^2 - 2(1)x + 1^2) + (y^2 + 2(4)y + 4^2) = 47 + 1^2 + 4^2
(x - 1)^2 + (y + 4)^2 = 64 = 8^2
r=8

7 0

3 years ago

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