I solved this problem by setting 240/80 equal to x/100 . Once you set them equal to each other, multiply 240 and 100 and divide the product by 80 and you get 300.
First, find what percentage of students had 3 or more by adding up your known percents:
45% + 23 % + 21% + x% = 100%
x = 11%
Since you're given that 96 students had 2 or more, you add up the percentages of 2 and 3 or more:
11 + 21 = 32%
Now set up a proportion that relates it to the whole:

This will allow you to find the total number of students at the school.
Cross multiplying and solving for x results in 300 total students.
Question 1:
45% had one or more absences. 45% of 300 students is
135 students.
Question 2:
As we found before, 11% of students had three or more. 11% of 300 is
33 students.
Let's assume
length of rectangle =L
width of rectangle =W
You enclose 3 sides of the garden with 40 feet of fencing
so, we get

now, we can solve for L

we know that
area of rectangle is


now, we can plug

now, we can solve for W

we can use quadratic formula


we can take anyone value ..because both are giving positive value
first dimensions:

now, we can find L


so, length is 34.142feet
width is 2.929 feet
Second dimensions:

now, we can find L


so, length is 5.858feet
width is 17.071 feet
=3(3z)2-3
=3(9z2)-3
=27z^2-3
=3(9z^2-1)
=3(3z+1)(3z-1)
Answer:
7+4
Step-by-step explanation:
hope it helps