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elena-s [515]
3 years ago
10

Angles ∝ and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

if β < ∝.
sin(x/2 + 2x) = cos(2x + 3x/2)
Mathematics
1 answer:
artcher [175]3 years ago
3 0
37.5 because it is just is
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The function f(x)=6x^3-54x^2-126x-8 is decreasing on the interval (-1,7) and it is increasing on the interval (-\infty, -1)\cup (7, \infty)

Step-by-step explanation:

To determine the intervals of increase and decrease of the function f(x)=6x^3-54x^2-126x-8, perform the following steps:

1. Differentiate the function

\frac{d}{dx}\left(6x^3-54x^2-126x-8\right)=\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\\frac{d}{dx}\left(6x^3\right)-\frac{d}{dx}\left(54x^2\right)-\frac{d}{dx}\left(126x\right)-\frac{d}{dx}\left(8\right)\\\\f'(x)=18x^2-108x-126

2. Obtain the roots of the derivative, f'(x) = 0

\mathrm{Factor\:out\:common\:term\:}18:\quad 18\left(x^2-6x-7\right)\\\\\mathrm{Factor}\:x^2-6x-7:\quad \left(x+1\right)\left(x-7\right)\\\\18x^2-108x-126:\quad 18\left(x+1\right)\left(x-7\right)\\\\18x^2-108x-126=0\quad :\quad x=-1,\:x=7

3.  Form open intervals with the roots of the derivative and take a value from every interval and find the sign they have in the derivative.

If f'(x) > 0, f(x) is increasing.

If f'(x) < 0, f(x) is decreasing.

On the interval \left(-\infty, -1\right), take x = -2,

f'(-2)=18(-2)^2-108(-2)-126=162  f'(x) > 0 therefore f(x) is increasing

On the interval \left(-1,7), take x = 0,

f'(0)=18(0)^2-108(0)-126=-126  f'(x) < 0 therefore f(x) is decreasing

On the interval \left(7, \infty\right), take x = 10,

f'(10)=18(10)^2-108(10)-126=594  f'(x) > 0 therefore f(x) is increasing

The function f(x)=6x^3-54x^2-126x-8 is decreasing on the interval (-1,7) and it is increasing on the interval (-\infty, -1)\cup (7, \infty)

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