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3 years ago

Select the correct answer from the drop-down menu.

Mathematics

1 answer:

Contact [7]3 years ago

4 0

Answer:

The correct option is C.

C) -x + 2

Step-by-step explanation:

In mathematics, the term which is being divided is called a dividend. The term by which the dividend is getting divided is called a divisor. The quotient is the term we get after dividing the dividend by a divisor.

Here in this case, the dividend is written.

-x² x x

which in the equation form is written as

-x² + x + x

add the x terms to simplify

-x² + 2x

The divisor is given as x, divide the equation by x:

(-x² + 2x)/x

(-x²/x) + (2x/x)

-x+2

Which is the quotient.

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Answer:

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3 years ago

Convert x2 + y2 -4x = 0 to polar form.

Bingel [31]

Answer:

$r(r-4\cos \theta)=0$

Step-by-step explanation:

We are given the following equation:

$x^2 + y^2 -4x = 0$

We have to convert it into polar form.

We put

$x = r \cos \theta\\y = r\sin \theta$

Putting values, we get:

$x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0$

is the required polar form.

7 0

3 years ago

Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6

Ivan

Step-by-step explanation:

If the parabola has the form

$y = a(x - h)^2 + k$ (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

$y = \dfrac{1}{6}(x - 8)^2 + 6$

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

$\text{focus} = (h, k +\frac{1}{4a})$

where $\frac{1}{4a}$ is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is