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3 years ago

10

A building is 222 feet tall and has 24 floors. The height of each floor is the same. What is the height of each floor?(Show your

work if you want)

2 answers:

Olenka [21]3 years ago

6 0

222/24= 9.25 each floor is 9.25 feet tall

katrin [286]3 years ago

4 0

May I see a file of it? link it.

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5000 - 1824 = 3176 left after the first week.

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3 years ago

A city-wide gardening club is up of men, women and children in the ratio 5:4:11.

Sever21 [200]

Answer:

Women: 448 Men: 560 Children: 1232

Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago