3 years ago

PLEASE HELP ME I BEG YOU

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

1- False

2- False

3- False

4-False

You might be interested in

Round 2.372 to the nearest tenth

creativ13 [48]

There is no ones place after the decimal so 3 is in the tenth place, so 2.4

8 0

3 years ago

What is the value of the discriminant for the quadratic equation -3=-x 2+2x

seraphim [82]

X=3,-1 your answer is right here

3 0

3 years ago

If 10 is added to each observation and the following data set what is the relationship between the original standard deviation a

jeyben [28]

Answer:

Step-by-step explanation:

7 0

3 years ago

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

3 years ago

What is lcm and gcf of 6a and 8b

Feliz [49]

Lcm is 24 and the gcf is 2

8 0

3 years ago

Read 2 more answers