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3 years ago

How do I solve 1/8x=5

2 answers:

8 0

1/8x = 5

1/8x = 5/1

Take reciprocal of both sides

8x/1 = 1/5

8x = 1/5 Divide both sides by 8

x = 1/5 ÷ 8

x = 1/5 * 1/8

x = 1/40

gizmo_the_mogwai [7]3 years ago

7 0

You multiply both sides by the reciprocal (flip fraction)
1/8--->8/1=8
So now multiply both sides by 8
1/8*8=0 (cancels out)
x=5*8
x=40

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Read 2 more answers

If $500 is invested at 8% annual interest, how much will be in the account after 3 years if it's compounded quarterly?

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FV= $634.12

Step-by-step explanation:

Giving the following formula:

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2 years ago

Can you please help with this question about exponential equations?

RSB [31]

Since $t$ represents the number of years passed since 2005, in 2005 we have $t=0$ , and in 2015 we have $t=10$ . Let $P_J(y),P_D(y)$ represent the profits of Jones and Davis, respectively, at year y.

We have

$P_J(2005) = 10(0.99)^0 = 10,\quad P_J(2015) = 10(0.99)^{10}\approx 9$

$P_D(2005) = 8(1.01)^0 = 8,\quad P_D(2015) = 8(1.01)^{10}\approx 9$

Choosing the best company somehow depends on how much time you can wait: Jones start with a higher value (10 vs 8), but it has a descending trend, because the multiplicative factor $0.99^t$ goes to zero as t grows.

On the other hand, Davis starts with a smaller value, but $1.01^t$ tends to infinity as t grows.

So, if you need an immediate result, the most valuable company is Jones, otherwise you're certain can Davis will eventually become bigger.

More precisely, we have

$8\cdot 1.01^t = 10\cdot 0.99^t \iff 0.8 = \left(\dfrac{0.99}{1.01}\right)^t \iff t\approx 11$

So, after 11 years, Davis will overcome Jones.

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3 years ago