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2 years ago

10

Avery had 25.92 in her wallet. If she bought lunch with 7 1/2 dollars from her wallet, how much did she have in her wallet after

lunch?

1 answer:

AleksAgata [21]2 years ago

6 0

25.92- 7.50
18.42 left in your wallet

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2) Rosa is making a board game that is 16 inches by 24 inches. She wants to use square tiles. What

solniwko [45]

Answer:

8x8

6

GCF

Step-by-step explanation:

3 0

3 years ago

20 weeks : 14 Days in simplest form? <br><br> Can you explain as well??

PilotLPTM [1.2K]

14 days = 2 weeks

20weeks : 14 days = 20 weeks : 2 weeks = 20 weeks / 2 weeks = 10:1

hope it helps!

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3 years ago

1/6×2/3<br> show me how to do it

hodyreva [135]

Multiple 6 with 3 and 1 with 2
2/18 = 19

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3 years ago

Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS

olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....$

where, n = number of trials (samples) taken = 36 couples

r = number of success

p = probability of success which in our question is probability

of a girl, i.e.; p = 0.5

<em><u>Let X = Numbers of girls in groups of 36 births </u></em>

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

<u>Mean</u>, E(X) = $n \times p$ = $36 \times 0.5$ = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

<u>Standard deviation</u>, S.D.(X) = $\sqrt{n\times p\times (1-p)}$

= $\sqrt{36\times 0.5\times (1-0.5)}$

= 3

3 0

2 years ago

2 taps A and B can fill a swimming pool in 3 hours. If turned on alone, it takes tap A 5 hours less than tap B to fill the same

vazorg [7]

Answer:

Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

Step-by-step explanation:

Let tap B fills the pool alone in the time = x hours

So in one hour part of pool will be filled = $\frac{1}{x}$

Another tap A when turned on, it takes time to fill the pool = x-5 hours

So in one hour part of the same pool filled = $\frac{1}{x-5}$

Now both the taps A and B are turned on then time taken to fill the pool = 3 hours.

Part of the pool filled in one hour by both the taps = $\frac{1}{3}$

Now we form an equation

Part of pool filled in one hour by tap A + Part of pool filled in one hour by tap B = Part of pool filled in one hour by both the taps when turned on

$\frac{1}{(x-5)}+\frac{1}{x}=\frac{1}{3}$

$\frac{x-5+1}{x(x-5)}=\frac{1}{3}$

$\frac{x-4}{x(x-5)}=\frac{1}{3}$

3(x - 4) = x(x - 5)

x² -5x = 3x - 12

x² - 8x + 12 = 0

x² - 6x - 2x + 12 = 0

x(x - 6) - 2(x - 6) = 0

(x -2)(x - 6) = 0

x = 2, 6 hours

We will take higher value of x as x = 6 hours for tap B.

Time taken by tap A = 6 - 4 = 2 hours.

Therefore, Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

4 0

3 years ago