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Advocard [28]
3 years ago
10

Avery had 25.92 in her wallet. If she bought lunch with 7 1/2 dollars from her wallet, how much did she have in her wallet after

lunch?​
Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0
25.92- 7.50
18.42 left in your wallet
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2 + 2 =? i need help
OLga [1]

Answer:

4

Step-by-step explanation:

Think of it this way. You have 2 sets of 2.

I I (This represents two)

I I (This represents the other two)

When you combine these, you get:

I I I I

If you count the tally marks, your answer is 4.

5 0
3 years ago
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Help me plz !!!?!?!?!
olganol [36]
I believe the answer is the second one I am in the same class.
5 0
3 years ago
This is just a test, but what’s 17 to the power of 9
Ganezh [65]

Answer:

118,587,876,497

Step-by-step explanation:

17^{9} = 17 * 17 * 17 * 17 * 17 * 17 * 17 * 17 * 17 = 118,587,876,497

7 0
3 years ago
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Erika bought 3 kilograms of cinnamon red hots and 1 kilogram of gummy bears for $21.00. Meanwhile, Irene bought 3 kilograms of c
grin007 [14]
Erika $21
3k of cinnamon
1g of gummies

Irene $39
3k of cinnamon
3k of gummies

c= cost of 1 kilogram of cinnamon
g= cost of 1 kilogram of gummies

Erika's Equation
3c + 1g= $21

Irene's Equation
3c + 3g= $39

Solve for one variable in equation one and substitute it in the other equation.

3c + 1g= 21
subtract 3c from both sides
g= 21 - 3c

Substitute g=21 - 3c in equation
3c + 3g= $39
3c + 3 (21 - 3c)= 39
multiply all in parentheses
3c + 63 - 9c= 39
63 - 6c= 39
subtract 63 from both sides
-6c= -24
c= $4

Substitute c=4 in equation to find g
3c + g= 21
3(4) + g= 21
12 + g= 21
subtract 12 from both sides
g= $9

ANSWER: The price of 1 kilogram of cinnamon red hots is $4. The cost of 1 kilogram of gummies is $9.

Hope this helps! :)
3 0
3 years ago
What values of k will make the line containing points (k,3) and (-2,1) parallel to the line through (5, K) and (1,0)
rjkz [21]

Answer:

k = -4 or 2

Step-by-step explanation:

For the lines to be parallel, the lines would need to be the same slope. This means to find the slope of each we would take the difference of the rise over the run.

\frac{1-3}{-2-k}=\frac{-2}{-2-k}

and

\frac{0-k}{1-5}=\frac{-k}{-4}

To find K, set them equal.

\frac{-2}{-2-k} = \frac{-k}{-4}\\-k(-2-k) = -2*-4\\2k+k^2=8\\k^2+2k-8=0

Factor the quadratic and solve for K.

(k+4)(k-2)=0

k+4=0 so k=-4

k-2=0 so k=2

4 0
3 years ago
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