Do you think more chemical reactions that occur in the human body are endothermic or exothermic? Justify your answer.

Chemistry

1 answer:

77julia77 [94]3 years ago

6 0

Answer:

Exothermic

Explanation:

We as humans do not absorb heat. A good way to think about it is that when we workout we use energy from our body which causes our body temperature to rise. The energy used from food maintains our blood, respiration, and other systems in optimal condition. This requires energy from our body which ends up leaving the body as heat.

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Explain how the following experimental errors affect the final calculation of the kilocalories per gram for a food item. Be spec

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Answer:

a) the final kilocalories per gram for food will be less because the mass was reduced

b)the final kilocalories per gram for food will be less since

c) the final kilocalories per gram for food will be less since the reaction will eventually go to completion

d) the final kilocalories per gram for food will be more.

Explanation:

a) the final kilocalories per gram for food will be less because the mass was reduced from 110.3 to 101.3g

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4 years ago

What information do the coefficients of a balanced equation give about the

ale4655 [162]

Answer:

B. The coefficients give the molar ration of the reactants

Explanation:

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3 years ago

Read 2 more answers

Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: hso4−+h2o⇌so42−+h3o+ identify the conjugate acid-

Angelina_Jolie [31]

The generic equation for a reaction between an acid and water is

$HX_{(aq)} + H_{2}O_{(aq)} --> X_{(aq)}^{-} + H_{3}O_{(aq)}^+$

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base ( $X^-$ ), and the conjugate acid-base pair is $HX$ - $X^-$ .

Hydrogen sulfate ( $HSO_{4}^-$ ) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water (( $H_{2}O$ ) to form the sulfate ( $SO_{4}^2-$ ) and hydronium ( $H_{3}O^+$ )ions.

$HSO_{4(aq)}^{-} + H_{2}O_{(aq)} --> SO_{4(aq)}^{2-} + H_{3}O_{(aq)}^+$

Based on the previous discussion, $SO_{4(aq)}^2-$ is identified to be the conjugate of the acid $HSO_{4(aq)}^-$ . Thus, the conjugate acid-base pair is $HSO_{4(aq)}^{-} - SO_{4(aq)}^{2-}$ .