Answer:
The van't Hoff factor is 2.55
Explanation:
Step 1: Data given
Osmotic pressure of CaCl2 = 0.585 atm
Osmotic pressure of urea = 0.237 atm
Concentration = 9.69 * 10^-3 M
Temperature = 25.0 °C
Step 2:
Π = iMRT
⇒ with Π = the osmotic pressure of CaCl2 = 0.585 atm
⇒ with i is the van't Hoff factor
⇒ with M = the molar concentration = 9.69 * 10^-3 M
⇒ with R = the gas constant = 0.0821 L*atm/mol*K
⇒ with T = the temperature = 25.0 °C = 298 K
0.605 atm = i(9.69 * 10^-3 M)(0.0821 L*atm/mol*K)(298K)
i = 2.55
The van't Hoff factor is 2.55
Chemical reaction: CH₃-CH(CH₃)-CH₂-SH + CH₃-CH(CH₃)-CH₂-SH →
CH₃-CH(CH₃)-CH₂-S-S-CH₂-CH(CH₃)-CH₃ + 2H⁺ + 2e⁻.
<span>The oxidation of thiols yield to a disulfide. T</span>hiol<span> </span><span>is an </span>organosulfur compound<span> that has a carbon-bonded </span>sulfhydryl<span> (R–SH) group. </span>The linkage S-S-bond<span> is called a </span>disulfide bridge.
Answer:
Mass = 199.2 g
Explanation:
Given data:
Mass in gram = ?
Number of atoms of C-12 = 100 atom
Solution:
First of all we will calculate the number of moles of C-12 in 100 atoms by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
100 atoms×1 mol / 6.022 × 10²³ atoms
16.6× 10²³ moles
Mass of C-12:
Mass = number of moles × molar mass
Mass = 16.6 × 10²³ mol × 12 g/mol
Mass = 199.2 g
Answer:
mixtures
Explanation:
Mixtures contain two or more substances that are relatively easy to separate. The individual components of a mixture can be physically separated from each other.