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3 years ago

Determine the equilibrium constant, Keq, at 25°C for the reaction

Chemistry

1 answer:

adelina 88 [10]3 years ago

3 0

Explanation:

The given chemical reaction is:

$2Br^- (aq) + I_2(s) Br_2(l) + 2I^- (aq)$

$E^ocell=oxidation potential of anode + reduction potential of cathode\\$

The relation between Eo cell and Keq is shown below:

$deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell$

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

$E^ocell= (-1.07+0.53)V\\=-0.54V$

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

$ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3$

Answer:

Keq=6.13x10^33

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For the reaction N2(g) + 3H2(g) ↔ 2NH3(g), the equilibrium constant, K, = 9.83 x 10-2 at a certain temperature and pressure.

pshichka [43]

The reaction is not at equilibrium and it is in the forward direction.

Given,

[N₂] = 0.910 mol / L

[H₂] = 0.3 mol / L

[NH₃] = 0.0081 mol / L

K = 9.83 x 10⁻²

The balanced chemical equation for the given reaction is,

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

The formula of equilibrium constant is given by,

K = [NH₃]² / [N₂] [H₂]²

9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]

⇒9.83 x 10⁻² = (0.00006561) / (0.0819)

⇒9.83 x 10⁻² = 0.0008010989

⇒0.00983 = 0.0008010989

LHS ≠ RHS

Hence, the reaction is not at equilibrium.

The reaction is in forward direction.

Learn more about direction of the reaction from the link given below.

brainly.com/question/10278602

#SPJ1

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2 years ago

Question 2: you have two systems: 1) solid gold and water 2) solid sodium and waterWhich one can spontaneously release energy an

Valentin [98]

Hey there!

Solid Sodium and water will react spontaneously and release energy. This is based on the reactivity series. Sodium is a highly reactive metal and hence, it is placed at the top of the reactivity series. This is because it loses its outermost electron very readily. When it comes in contact with water, it reacts with it violently to form sodium hydroxide and hydrogen gas. This reaction is exothermic and hence, accompanied with a release of energy. Gold lies at the bottom of the reactivity series as it is very stable and does not give away its outermost electrons easily. Therefore, when it comes in contact with water, there is no reaction and no release of energy.

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4 years ago

What is the value of work done on an object when a 10-newton force moves it 30 meters and the angle between the force and the di

statuscvo [17]

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3 years ago

63.15 mL of calcium hydroxide is required to titrate 18.9 mL of a 0.200 M H3PO4 solution. What is the molarity of the basic solu

Kruka [31]

Answer:

0.0898M is the molarity of the basic solution

Explanation:

The reaction of calcium hydroxide, Ca(OH)₂ with H₃PO₄ is:

3 Ca(OH)₂ + 2 H₃PO₄ → 6H₂O + Ca₃(PO₄)₂

To solve this question we must find the moles of H3PO4 that react. With the moles and the rection we can find the moles of Ca(OH)2. Using its volume we can find its molarity:

<em>Moles H3PO4:</em>

0.0189L * (0.200mol / L) = 0.00378 moles H3PO4

<em>Moles Ca(OH)2:</em>

0.00378 moles H3PO4 * (3mol Ca(OH)2 / 2mol H3PO4) = 0.00567 moles Ca(OH)2

<em>Molarity:</em>

0.00567 moles Ca(OH)2 / 0.06315L =

<h3>0.0898M is the molarity of the basic solution</h3>

6 0

3 years ago

Will give brainliest to whoever answers the right answer.

zaharov [31]

Answer:

option b is correct

as it have same number of atoms on both the reactant and product side.

4 0

3 years ago