The reaction is not at equilibrium and it is in the forward direction.
a.
Given,
[N₂] = 0.910 mol / L
[H₂] = 0.3 mol / L
[NH₃] = 0.0081 mol / L
K = 9.83 x 10⁻²
The balanced chemical equation for the given reaction is,
N₂(g) + 3H₂(g) ⇄ 2NH₃(g)
The formula of equilibrium constant is given by,
K = [NH₃]² / [N₂] [H₂]²
9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]
⇒9.83 x 10⁻² = (0.00006561) / (0.0819)
⇒9.83 x 10⁻² = 0.0008010989
⇒0.00983 = 0.0008010989
LHS ≠ RHS
Hence, the reaction is not at equilibrium.
b.
The reaction is in forward direction.
Learn more about direction of the reaction from the link given below.
brainly.com/question/10278602
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Hey there!
Solid Sodium and water will react spontaneously and release energy. This is based on the reactivity series. Sodium is a highly reactive metal and hence, it is placed at the top of the reactivity series. This is because it loses its outermost electron very readily. When it comes in contact with water, it reacts with it violently to form sodium hydroxide and hydrogen gas. This reaction is exothermic and hence, accompanied with a release of energy. Gold lies at the bottom of the reactivity series as it is very stable and does not give away its outermost electrons easily. Therefore, when it comes in contact with water, there is no reaction and no release of energy.
When a 10 newton force is applied to move 30 meters with an angle of displacement of 25 degrees, the work done is calculated using the formula W= F*d*sin ∅ .Substituting the given dimensions, the answer to this problem is 126.79 joules.
Answer:
0.0898M is the molarity of the basic solution
Explanation:
The reaction of calcium hydroxide, Ca(OH)₂ with H₃PO₄ is:
3 Ca(OH)₂ + 2 H₃PO₄ → 6H₂O + Ca₃(PO₄)₂
To solve this question we must find the moles of H3PO4 that react. With the moles and the rection we can find the moles of Ca(OH)2. Using its volume we can find its molarity:
<em>Moles H3PO4:</em>
0.0189L * (0.200mol / L) = 0.00378 moles H3PO4
<em>Moles Ca(OH)2:</em>
0.00378 moles H3PO4 * (3mol Ca(OH)2 / 2mol H3PO4) = 0.00567 moles Ca(OH)2
<em>Molarity:</em>
0.00567 moles Ca(OH)2 / 0.06315L =
<h3>0.0898M is the molarity of the basic solution</h3>
Answer:
option b is correct
as it have same number of atoms on both the reactant and product side.