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Karolina [17]
3 years ago
10

Explain how an owl captures energy from the sun when it eats a mouse​

Chemistry
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

The mouse Eats plants that use the sun as a food source

Explanation:

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Answer:

Nitrate is a polyatomic ion with the molecular formula NO⁻₃ and a molecular mass of 62.0049 u. Organic compounds that contain the nitrate ester as a functional group are also called nitrates.

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a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3
aksik [14]

\huge\boxed{♔︎Answer♔︎}

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

half life time period = 3 hours

(a) The weight of sample after 3 hours

\textsf{ No. of half lives} =  \sf  \cancel\frac{3}{3}  = 1

The fraction of sample left

\sf  { \frac{1}{2} }^{1}  =  \frac{1}{2}

Mass of the sample left

\sf \frac{1}{2}  \times 120 =   \cancel\frac{120}{2}  = 60g

<u>6</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>3</u><u> </u><u>hours</u>

(b) The weight of sample after 6 hours

\textsf{ No. of half lives} =  \sf   \cancel\frac{6}{3}  = 2

The fraction of the sample left

\sf   { \frac{1}{2} }^{2}  =  \frac{1}{2}  \times  \frac{1}{2}  =  \frac{1}{4}

Mass of the sample left

\sf \frac{1}{4}  \times 120 =   \cancel\frac{120}{4}  = 30g

<u>3</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>6</u><u> </u><u>hours</u>

(c) The weight of sample after 9 hours

\textsf {No. of half lives} =  \sf   \cancel\frac{9}{3}  = 3

The fraction of sample left

\sf { \frac{1}{2} }^{3}  =  \frac{1}{2}  \times  \frac{1}{2}  \times  \frac{1}{2} =  \frac{1}{8}

Mass of sample left

\sf  \frac{1}{8}  \times 120 =  \cancel \frac{120}{8}  = 15g

<u>1</u><u>5</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>9</u><u> </u><u>hours</u><u>.</u>

3 0
2 years ago
What sort of chemical hazard is thalidomide?
ValentinkaMS [17]
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7 0
4 years ago
Which has a higher electronegativity phosphorus or sodium
Yuliya22 [10]

Answer:

it is phosphorus it has o most 2 times as much  electromagnetically

Explanation:

4 0
3 years ago
What should be the mole fraction of O2 in the gas mixture the diver breathes in order to have the same partial pressure of oxyge
Nutka1998 [239]

The question is incomplete, here is the complete question:

A scuba diver is at a depth of 355 m, where the pressure is 36.5 atm.

What should be the mole fraction of O_2 in the gas mixture the diver breathes in order to have the same partial pressure of oxygen in his lungs as he would at sea level? Note that the mole fraction of oxygen at sea level is 0.209.

<u>Answer:</u> The mole fraction of oxygen in the gas mixture is 0.00573

<u>Explanation:</u>

To calculate the partial pressure, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}      ........(1)

where,

p_A = partial pressure of oxygen at sea level = ?

p_T = total pressure at sea level = 1.00 atm

\chi_A = mole fraction of oxygen at sea level = 0.209

Putting values in equation 1, we get:

p_{O_2}=1.00atm\times 0.209\\\\p_{O_2}=0.209atm

As, partial pressure of the oxygen in the diver's lungs is equal to the partial pressure of oxygen at sea level

We are given:

p_T=36.5atm\\p_{O_2}=0.209atm

Putting values in equation 1, we get:

0.209atm=36.5atm\times \chi_{O_2}\\\\\chi_{O_2}=\frac{0.209}{36.5}=0.00573

Hence, the mole fraction of oxygen in the gas mixture is 0.00573

3 0
3 years ago
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