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larisa86 [58]
3 years ago
6

the number below and to the right of an element in a chemical formula. It represents the number of atoms of that element in chem

ical compound or molecule.
Chemistry
2 answers:
RideAnS [48]3 years ago
6 0
The statement is true, if that was your question
nydimaria [60]3 years ago
5 0

Answer:

The answer was subscript

Explanation:

You might be interested in
Zinc phosphate is used as a dental cement. A 50.00-mg sample is broken down into its constituent elements and gives 16.58 mg oxy
cricket20 [7]

Answer:

Zn3P2O8

Explanation:

In this particular question, it is necessary to convert the respective masses to percentages. We convert to percentages by placing each mass over the total mass and multiplying by 100%. Since the total is 50mg, conversion to percentage can be done by multiplying the masses by 2 as 100/50 is 2

For Oxygen = 16.58 * 2 = 33.16%

For phosphorus = 8.02 * 2 = 16.04%

For zinc = 25.40 * 2 = 50.80%

We then proceed to divide these percentages by their respective atomic masses. The atomic mass of oxygen, phosphorus and zinc are 16, 31 and 65 respectively.

O = 33.16/16 = 2.0725

P = 16.04/31 = 0.5174

Zn = 50.80/65 = 0.7815

Now, we divide by the smallest value which is that of the phosphorus

O = 2.0725/0.5174 = 4

P = 0.5174/0.5174 = 1

Zn= 0.7815/0.5174 = 1.5

Now, we need to multiply through by 2. This yields: O = 8, P = 2 and Zn = 3

The empirical formula is thus: Zn3P2O8

7 0
3 years ago
Chemical formula for tin iv carbide
aniked [119]

Answer:

Explanation:

Sn(WC)2

if it is tungsten carbide this should be correct but there are many versions of carbide

Sn(MC2)2

could also be possible

the 2 next to MC should be a subscript

3 0
3 years ago
What are the elements in group 3-12 called
Wittaler [7]

Answer:

Transition Metals

Explanation:

The elements in groups 3-12 are called Transition Metals. These groups contain metals that usually form multiple cations. All other groups on the table (1, 2, 13-18) are called Main Group Elements.

5 0
3 years ago
From the balanced reaction:
Lelu [443]

Answer:

The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.

7 0
3 years ago
What is the pressure if 0.567 moles of gas occupy 4.5 liters at a temperature of 300.0 K?
kakasveta [241]
The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
3 0
3 years ago
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