PV = nRT. Where P = pressure, V = volume, n = number of moles, R = universal gas constant and T = temperature. Hope this helps!
Answer:

Explanation:
We must do the conversions
mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of O₂
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 180.16
C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O
m/g: 18.1
(a) Moles of C₆H₁₂O₆

b) Moles of O₂
Answer:
A solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.
Explanation:
7 strong acids are strong electrolytesHCl, HBr, HI, HNO3, HCIO3, HCIO4, and H2SO4
3 strong bases are strong electrolytes<span>OH, KOH, and NaOH</span>
Answer:
The initial temperature of helium was T1 = 232.23 K
Explanation:
Given data:
Initial volume V1 = 5 L
Initial pressure P1 = 699 mmHg
Final pressure P2 = 800 mmHg
Final volume V2 = 5.7 L
Final temperature T2= 303 K
Initial temperature T1 = ?
Solution:
Formula:
P1V1/T1 = P2V2/T2
T1 = T2 × P1V1/P2V2
T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L
T1 = 1058985/ 4560
T1 = 232.23 K
initial temperature of helium was 232.23 k.