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Shtirlitz [24]
3 years ago
5

How do you know if the girl your dating is into the size or onto personality? 100 POINTS

Chemistry
2 answers:
nignag [31]3 years ago
4 0

Answer:

here

Explanation:

My guess is if she's into you for your size she's gonna want to have s## alot, but if she's into your personality she wants to hang out with you and compliments you this is my guess so sorry if this isnt good

Alex Ar [27]3 years ago
4 0

Answer:

they want to kiss you and you know, have s6x a lot, but if personalit, they would take everything slow and give you space :)

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Which of these periods contain elements with electrons in s, p, d, and forbitals?
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3 years ago
A gas occupies a volume of 4.50 L at 44 kPa. What would be the new volume at 50 kPa?
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Explanation:

P1= 44 kpa

P2= 50 kpa

V1= 4.50 L

V2= ?

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2 years ago
what is the limiting reactant when 1.50g of lithium and 1.50 g of nitrogen combine to form lithium nitride, a component of advan
PSYCHO15rus [73]
<h3>Answer:</h3>

Limiting reactant is Lithium

<h3>Explanation:</h3>

<u>We are given;</u>

  1. Mass of Lithium as 1.50 g
  2. Mass of nitrogen is 1.50 g

We are required to determine the rate limiting reagent.

  • First, we write the balanced equation for the reaction

6Li(s) + N₂(g) → 2Li₃N

From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.

  • Second, we determine moles of Lithium and nitrogen given.

Moles = Mass ÷ Molar mass

Moles of Lithium

Molar mass of Li = 6.941 g/mol

Moles of Li = 1.50 g ÷ 6.941 g/mol

                   = 0.216 moles

Moles of nitrogen gas

Molar mass of Nitrogen gas is 28.0 g/mol

Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol

                                     = 0.054 moles

  • According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
  • Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
  • On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.

Thus, Lithium is the limiting reagent while nitrogen is in excess.

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3 years ago
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