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mixas84 [53]
3 years ago
15

What is the balance equation for

Chemistry
1 answer:
murzikaleks [220]3 years ago
7 0

1st one

2_2_2

2nd one

3_1_1_3

i looked it up

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A,B and C have the following solubilities in 100 mL of water at 25°C, respectively: 15g, 35 g and 65 g. If 75 g of each are adde
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<u>Only C can dissolve in water because its solubility is greater than 0.375 g/mL</u>

<u>C dissolves completely</u>

22.5 g of A remain undissolved in 100 mL of water

2.5 g of B remain undissolved  in 100 mL of water

<u></u>

Explanation:

Solubility : The amount of salt that can be dissolved in a given volume of solvent at a particular temperature .

Solubility = \frac{mass}{volume}

For each salt the solubility of 75 g in  200 mL water is

Solubility = \frac{75}{200}

0.375 g/mL

This mean 1 ml of water has 0.375 g of A , B and C

<u>100 mL of water contain = 37.5 g of each salt A , B,C</u>

In the question , the solubility of A , B and C in 100 are given as :

A =  15 g : It means maximum 15 g of A can dissolve in 100 mL

Solubility = \frac{15}{100} = 0.15 g/mL

B = 35 g  : It means maximum 35 g of B can dissolve in 100 mL

Solubility = \frac{35}{100} = 0.35 g/mL

C = 65 g : It means maximum 65 g of A can dissolve in 100 mL

Solubility = \frac{65}{100} = 0.65 g/mL

Since ,Solubility of A and B is less than 0.375 g/mL

<u>So A and B  can't dissolve in water at 25°C</u>

A is excess by 37.5 - 15 = 22.5 g

B is in excess by 37.5 - 35 = 2.5 g

<u>Hence 22.5 g of A remain undissolved</u>

<u>Hence  2.5 g of B remain undissolved </u>

<u>Only C can dissolve in water because its solubility is greater than 0.375 g/mL</u>

<u></u>

6 0
4 years ago
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