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PilotLPTM [1.2K]
4 years ago
11

BRAINLIESTTT ASAP!!! PLEASE HELP ME :) Describe Chadwick’s work in Chemistry.

Chemistry
2 answers:
algol [13]4 years ago
7 0

Sir James Chadwick was the scientist who discovered the neutron. The electron and proton had already been found but with the neutron known, we knew everything that made up our universe. He won the 1935 Nobel Peace Prize for his discovery.

Pie4 years ago
3 0

Answer:

Here's what I get.

Explanation:

James Chadwick is best known for his discovery of the neutron in 1932.

Earlier research

Before 1932, the only subatomic particles known were the electron and the proton. Scientists thought that the nucleus contained both protons and electrons.

For example, they thought a helium atom contained four protons and two electrons, with two electrons orbiting the nucleus.

In 1928, German physicists discovered that beryllium nuclei,  when bombarded with α particles, emitted a strange type of extremely energetic radiation. It had no charge, because it wasn't deflected by electric or magnetic fields. Neither was it γ-rays, because it did not discharge an electroscope.

In 1932 Irène and Frédéric Joliot-Curie discovered that the radiation knocked protons  loose from paraffin, and they could be detected by a Geiger counter. They, too, thought the radiation was some type of strange γ-rays .

Chadwick's work

Chadwick did not believe their explanation.

He quickly repeated their experiments with paraffin and also used other substances as targets.

He couldn't observe the uncharged radiation directly, but he could count the protons and measure their energies as they were ejected from the targets.

By working backwards and using the  laws of conservation of energy and momentum, Chadwick concluded that the radiation must consist of neutral particles with a mass 1.0067 times  that of a proton.

He had discovered the neutron.

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Tris base has a molecular weight of 121 g/mol. How many grams of tris base would you need to make 250ml of a 200mM SOLUTION
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Answer:

6.05 g

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

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V = volume of solution in liter ,

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Since,

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Putting the respective values ,

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n = 0.05 mol ( calculated above )

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0.05 mol = w / 121 g/mol

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w = 6.05 g

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