Answer:
See below
Explanation:
You have to heat the calorimeter to 100 C from 20 C
this will take .20 kg * 390 j /kg-C * 80 C = <u>6240 j</u>
You have to heat the mass of water to boiling point (100 C ) from 20C
this will take
.50 kg * 4182 j/kg-C * 80 = <u>167,280 j </u>
AND you have to add enough heat to boil off .03 kg of water:
.03 kg * (2260000 j/kg-C ) =<u> 67,800 j</u>
<u />
Power = joules / sec = (6240 + 167280 + 67800) / 274.8 =<u> 878 watts </u>
<u />
<u>Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....</u>
They has been very successful but they are very expensive to operate that is your answer I hope this helps
it cannot be reuse and replaced for long period of time.hope it helps u
Answer:
Explanation:
Lol thats big tufffffffffvffffffftg
fuf
