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yKpoI14uk [10]
3 years ago
14

Find the acceleration of an object that has a mass of 6 kg, if it is acted upon by a net force of 42 N.

Physics
1 answer:
pychu [463]3 years ago
7 0

Answer:

7 m/s²

Explanation:

The formula for force is:

f= m*a

We want to find acceleration, so we must rearrange the formula for a. Divide both sides of the equation by m

\frac{f}{m}=\frac{m*a}{m}

\frac{f}{m}=a

Acceleration can be found by dividing the force by the mass.

The force is 42 newtons and the mass is 6 kilograms. A newton is equal to 1 kg * m/s², therefore the force is 42 kg* m/s².

f= 42 kg*m/s^2\\m=6 kg

Substitute the values into the formula.

a=\frac{f}{m}

a=\frac{42 kg*m/s^2}{6kg}

Divide. When we divide, the kg in the numerator and denominator will cancel each other out.

a=\frac{42}{6}m/s^2

a= 7 m/s^2

The acceleration of the object is 7 meters per square seconds.

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A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu
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Answer:

The frictional torque is \tau  = 0.2505 \ N \cdot m

Explanation:

From the question we are told that

   The mass attached to one end the string is m_1 =  0.341 \ kg

   The mass attached to the other end of the string is  m_2 =  0.625 \ kg

    The radius of the disk is  r = 9.00 \ cm  = 0.09 \ m

At equilibrium the tension on the string due to the first mass is mathematically represented as

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The  frictional torque that must be exerted is mathematically represented as

      \tau  =  (T_2 * r ) - (T_1 * r )

substituting values  

     \tau  =  ( 6.125 * 0.09 ) - (3.342  * 0.09 )

     \tau  = 0.2505 \ N \cdot m

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3 years ago
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