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yKpoI14uk [10]
2 years ago
14

Find the acceleration of an object that has a mass of 6 kg, if it is acted upon by a net force of 42 N.

Physics
1 answer:
pychu [463]2 years ago
7 0

Answer:

7 m/s²

Explanation:

The formula for force is:

f= m*a

We want to find acceleration, so we must rearrange the formula for a. Divide both sides of the equation by m

\frac{f}{m}=\frac{m*a}{m}

\frac{f}{m}=a

Acceleration can be found by dividing the force by the mass.

The force is 42 newtons and the mass is 6 kilograms. A newton is equal to 1 kg * m/s², therefore the force is 42 kg* m/s².

f= 42 kg*m/s^2\\m=6 kg

Substitute the values into the formula.

a=\frac{f}{m}

a=\frac{42 kg*m/s^2}{6kg}

Divide. When we divide, the kg in the numerator and denominator will cancel each other out.

a=\frac{42}{6}m/s^2

a= 7 m/s^2

The acceleration of the object is 7 meters per square seconds.

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Consider one such cell where the magnitude of the potential difference is 65 mV, and the inner surface of the membrane is at a h
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Answer: W = 1.04.10^{-20} J

Explanation: Since the potassium ion is at the outside membrane of a cell and the potential here is lower than the potential inside the cell, the transport will need work to happen.

The work to transport an ion from a lower potential side to a higher potential side is calculated by

W=q.\Delta V

q is charge;

ΔV is the potential difference;

Potassium ion has +1 charge, which means:

p = 1.6.10^{-19} C

To determine work in joules, potential has to be in Volts, so:

\Delta V=65.10^{-3}V

Then, work is

W=1.6.10^{-19}.65.10^{-3}

W=1.04.10^{-20}

To move a potassium ion from the exterior to the interior of the cell, it is required W=1.04.10^{-20}J of energy.

8 0
3 years ago
A 5.0 kg object moving at 5.0 m/s. KE = mv2 times 1/2
steposvetlana [31]

Answer: KE = 62.5J

Explanation:

Given that

Mass of object = 5kg

kinetic energy KE = ?

velocity of object = 5m/s

Since kinetic energy is the energy possessed by a moving object, and it depends on the mass (m) of the object and the velocity (v) by which it moves. Therefore, the object has kinetic energy.

i.e K.E = 1/2mv^2

KE = 1/2 x 5kg x (5m/s)^2

KE = 0.5 x 5 x 25

KE = 62.5J

Thus, the object has 62.5 joules of kinetic energy.

5 0
3 years ago
Because P and S waves travel faster through the Earth's mantle than through Earth's crust, scientists know that the mantle is __
larisa [96]
B. liquid and less denser
6 0
3 years ago
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Katelyn (55 kg) is practicing a drop jump in the biomechanics lab. She steps off a plyometrics box, lands on the force plate, an
suter [353]

Answer:

J = 357.5 kg*m/s

Explanation:

  • The impulse exerted on Katelyn when she was on the force plate, is equal to the change in her momentum, according to Newton's 2nd Law.
  • Assuming as the positive direction the upward direction (coincident with the positive y-axis) we can express the initial momentum as follows:

       p_{o} = m*v_{o} = 55 kg * (-3.0 m/s)  (1)

  • By the same token, the final momentum is as follows:

       p_{f} = m*v_{f} = 55 kg * (3.5 m/s)  (2)

  • As we have already said, the impulse J is just equal to the change in momentum, i.e., the difference between (2) and (1):

      J = p_{f} - p_{o} = m* (v_{f} -v_{o}) = 55 kg* (3.5m/s- (-3.0m/s)) = 357.5 kg*m/s (3)

5 0
2 years ago
.<br> Why are objects that fall near Earth's surface rarely in free fall?
gtnhenbr [62]

Answer:

Objects that fall near Earth’s surface are rarely in free fall.

"Free fall" is the situation where the ONLY force on an object is

the force of gravity, and nothing else.

Objects near Earth's surface are almost always surrounded by air.

If they are falling, then the air is exerting forces on them, and they

are not in "free fall".

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Explanation:

8 0
3 years ago
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