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yKpoI14uk [10]
3 years ago
14

Find the acceleration of an object that has a mass of 6 kg, if it is acted upon by a net force of 42 N.

Physics
1 answer:
pychu [463]3 years ago
7 0

Answer:

7 m/s²

Explanation:

The formula for force is:

f= m*a

We want to find acceleration, so we must rearrange the formula for a. Divide both sides of the equation by m

\frac{f}{m}=\frac{m*a}{m}

\frac{f}{m}=a

Acceleration can be found by dividing the force by the mass.

The force is 42 newtons and the mass is 6 kilograms. A newton is equal to 1 kg * m/s², therefore the force is 42 kg* m/s².

f= 42 kg*m/s^2\\m=6 kg

Substitute the values into the formula.

a=\frac{f}{m}

a=\frac{42 kg*m/s^2}{6kg}

Divide. When we divide, the kg in the numerator and denominator will cancel each other out.

a=\frac{42}{6}m/s^2

a= 7 m/s^2

The acceleration of the object is 7 meters per square seconds.

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Answer: The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

Explanation:

You can find the current in amperes using ohms and watts from this formula:

I = \sqrt{\frac{P}{R} }

Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.

You can then substitute 60 and 55 into the equation to find I:

I = \sqrt{\frac{55}{60} } \\I = \frac{\sqrt{55} }{\sqrt{60} }

Then, simplify the denominator:

I = \frac{\sqrt{55} }{2\sqrt{15} }

Rationalize the denominator:

I = \frac{\sqrt{55} }{2\sqrt{15} } * \frac{\sqrt{15} }{\sqrt{15} } = \frac{\sqrt{825} }{30}

Simplify the numerator by finding its factors:

I = \frac{5\sqrt{33} }{30} = \frac{\sqrt{33} }{6}

The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

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3 years ago
Determine the amount of work done by the engine of a car with a mass of 2500 kg when it accelerates from 45 mph to 65 mph. (Use
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Answer:

amount of work done, W = 549.36 kJ

Given:

mass of a car engine, m = 2500 kg

initial velocity, u = 45 mph

final velocity, v = 65 mph

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We know that 1 hour = 3600 s

Now, velocities in m/s are given as:

u = 45 mph = \frac{45\times 1609}{3600} = 20.11 m/s

v = 65 mph =  \frac{65\times 1609}{3600} = 29.05 m/s

Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:

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Why can rock avalanches move downslope at speeds exceeding 200 km/hr (125 mi/hr)?
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