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pshichka [43]
3 years ago
15

This is my first question don’t really know how to use this app yet lol but somebody answer it for me pls!! Seded the corredare

Physics
1 answer:
miskamm [114]3 years ago
7 0
3x6



(This just for extras )
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Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
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2hrs and some mins

Explanation:

bc 2×36= 17 =)

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What is the gravitational force on a 35.0 kg object standing on the Earth's surface?
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A mass of 5kg accelerates at 3m/s/s, how much force was put on it?
goldfiish [28.3K]

Answer:

15N

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Read 2 more answers
A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the
Mademuasel [1]

Answer:

a)

u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)    (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s

Then, you obtain by replacing in (1):

6in = 0.499 ft

u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)

b.

mass, m = 48lb

c.

b = 144.76 lb/s

8 0
3 years ago
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