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3 years ago

Write down the equation of a line parallel to y = 3x + 2

Mathematics

1 answer:

vichka [17]3 years ago

8 0

Answer:

y= 3x - 15

Step-by-step explanation:

parallel lines have the same slope, but different y intercepts

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n200080 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Leni [432]

Answer:

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Vertical Asy: 4
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Y intercept: 2
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3 years ago

Using the formula d= rt, rearrange it to highlight time , t.

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Step-by-step explanation:

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3 years ago

Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th

mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$g(x) = 3x^{2} - 42a + 135$

$a = 3, b = -42, c = 135$

$\bigtriangleup = (-42)^{2} - 4*3*135 = 144$

$x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9$

$x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5$

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

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