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cupoosta [38]
3 years ago
12

Write down the equation of a line parallel to y = 3x + 2

Mathematics
1 answer:
vichka [17]3 years ago
8 0

Answer:

y= 3x - 15

Step-by-step explanation:

parallel lines have the same slope, but different y intercepts

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riadik2000 [5.3K]

Answer:

30 more bags

Step-by-step explanation:

7 0
3 years ago
Need an answer fast!!!
trapecia [35]

Answer:

The length of the line segment is of 5.9 units.

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between these two points is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

How long is the line segment?

The distance between points P and Q. So

P(1,3), and Q(4,8).

D = \sqrt{(4-1)^2+(8-3)^2} = \sqrt{3^2 + 5^2} = \sqrt{34} = 5.9

The length of the line segment is of 5.9 units.

4 0
2 years ago
Solve each proportion.
Maslowich
To solve this question you need to cross multiply

So first do 3(2x+1) = 4(3x-2)
Which gives you 6x+1 = 12x-8

Now you solve it like a normal equation
6x+1 = 12x-8
9 = 6x
3/2 = x
3 0
2 years ago
Which of the following are incorrect expressions for slope?
vfiekz [6]

Answer:

Option B and C are correct.

\frac{x_2-x_1}{y_2-y_1}

\frac{run}{rise} are the expression incorrect for slope

Step-by-step explanation:

Slope is defined as the change in the dependent variable  relative to the change in the dependent variable

or the ratio of the horizontal changes to vertical changes between any two points on the graph of the line.

The vertical changes between any two points is rise

The horizontal changes between any two points is run.

Formula for slope is given by:

For any two points (x_1, y_1) and (x_2, y_2)

then slope is:

\text{Slope} =\frac{rise}{run}= \frac{y_2-y_1}{x_2-x_1}

or we can write this as:

Δy = y_2-y_1

Δx = x_2-x_1

⇒\text{Slope} = \frac{\triangle y}{\triangle x}

Therefore, the expression which are incorrect for slope  are;

\frac{x_2-x_1}{y_2-y_1}

\frac{run}{rise}

8 0
3 years ago
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My name is Ann [436]

Answer:

Our eyes are sensitive to all electromagnet waves with a wavelength longer than infrared

Step-by-step explanation:

I hope this helps :) good luck!

4 0
3 years ago
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