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3 years ago

100 points! Formation of an Ion

2 answers:

6 0

Given the chemical formula Al2O3 and every oxygen ion (combined with an aluminum ion) has a charge of -2, the total negative charge is -2x3 = -6.

As Al2O3 is neutral, the total positive charge must be 6. The charge of each aluminum ion is 6/2 = 3.

An uncharged aluminum atom must lose 3 electrons so that it will bond with oxygen.

RUDIKE [14]3 years ago

5 0

$\huge\bold {Answer}$

Aluminum ions have a charge of +3. This means that the atoms have three more protons than electrons. In order to add electrons to aluminum ions, the purification process therefore requires a large amount of electricity.

Uncharged Aluminum atom must need to lose it's electrons,in order to form the bond with oxygen which has vacant orbitals

ion
atom that has a positive or negative charge because it lost or gained one or more electrons

chemical bond
the attractive force that holds atoms or ions together

ionic bond
a chemical bond in which one atom loses an electron and the other atom gains electrons to form ions

chemical formula
a combination of chemical symbols and numbers to represent a substance

covalent bond
bond formed by the sharing of electrons between atoms

Thanks

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How many grams of Ni are formed from 55.3 g of Ni2O3? 2Ni2O3(s)⟶4Ni(s)+3O2(g)

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Answer:

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Explanation:

2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)

First we convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃, using its molar mass:

55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃

Then we convert 0.334 moles of Ni₂O₃ into moles of Ni, using the stoichiometric coefficients of the balanced reaction:

0.334 mol Ni₂O₃ * $\frac{4molNi}{2molNi_2O_3}$ = 0.668 mol Ni

Finally we calculate how much do 0.668 Ni moles weigh, using the molar mass of Ni :

0.668 mol Ni * 58.69 g/mol = 39.2 g

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