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Chemistry

1 answer:

NeTakaya3 years ago

7 0

sorry i don't know the answer i'm really sorry

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When N,N-Dimethylaniline is treated with bromine, ortho and para products are observed. However, when N,N-Dimethylaniline is tre

lilavasa [31]

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

6 0

2 years ago

This is an impossible formula. Pretend it is real.

guapka [62]

There are eight moles of oxygen atoms in 1 mole of $Mn_{9}(ClO_{4}) _{2}$ .

<h3>What is the number of moles of oxygen atoms?</h3>

We know that a compound is composed of atoms. The atoms that make up the molecule are chemically combined. It is usual that the number of atoms in the compound would correspond with the chemical formula.

Now we have the compound $Mn_{9}(ClO_{4}) _{2}$ . In one mole of the compound we have;