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Law Incorporation [45]
3 years ago
13

Solution A contains 5 molecules of albumin (protein) and solution B contains 12 molecules of glucose. The solutions are separate

d by a membrane. What way will water move? A. water will move from solution B to solution A because albumin is larger in size B. ]water will move from solution B to solution A because albumin is in lower concentration C. water will move from solution A to solution B because glucose is in higher concentrations D. water will move from solution A to solution B because glucose is smaller in size

Chemistry
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:

C. Water will move from solution A to solution B because glucose is in higher concentration.

Explanation:

In osmosis, the molecules of solvent will pass through a semipermeable membrane from a less concentrated to a more concentrated solution.

Solution B is more concentrated, so the water will move from A to B.

A and D are wrong, because the size of the solute particles does not control the direction of osmosis.

B is wrong because water moves to the more concentrated solution.

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The net force on an object that is accelerating at a rate of 4 m/sec is 255 N. What is the mass of the object in kg?
aleksklad [387]

Answer:

Given - acc = 4 m/ s^2

Force = 255 N

To find = mass

Solution -

Using the formula,

f = m \times a

255 = Mass × 4

255 /4 = Mass

63.75 = Mass

1 N = kg m/s^2

63.75 kg = Mass

7 0
3 years ago
When the following oxidation-reduction occurs, what is the balanced reduction half-reaction after the electrons in both half rea
Lostsunrise [7]

Answer :  The balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced redox reaction is :

Al(s)+Cu^{2+}(aq)\rightarrow Al^{3+}(aq)+Cu(s)

The half oxidation-reduction reactions are:

Oxidation reaction : Al\rightarrow Al^{3+}+3e^-

Reduction reaction : Cu^{2+}+2e^-\rightarrow Cu

In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

Oxidation reaction : 2Al\rightarrow 2Al^{3+}+6e^-

Reduction reaction : 3Cu^{2+}+6e^-\rightarrow 3Cu

The balanced redox reaction will be:

2Al(s)+3Cu^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Cu(s)

Thus, the balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

6 0
3 years ago
Select the correct answer.
Sladkaya [172]

Answer:

Explanation:

5 0
3 years ago
Upon consideration of the SiO2–Al
Grace [21]

The phase's composition is as follows: 27

What is the alloy's composition?

Both have mass fractions of w a = w b = 0.5.

A-B alloy composition; C o = 57 wt% B - 43 wt% A

C b = 87 wt% B - 13 wt% A is the new phase composition.

Using the Lever rule, we can calculate the mole fraction (x i) or mass fraction (w i) of each phase of a binary equilibrium phase as follows:

W a = W b = 0.5

This provides us with;

0.5 = (C b - C o)/(C b - C a)

(87 - 57)/(87 - C a) = 0.5

30/0.5 = 87 - C a

60 = 87 - C a

C a = 87 - 60

C a = 27

To learn more about composition please click on below link

brainly.com/question/13808296

#SPJ4

5 0
2 years ago
Calculate the equilibrium constant at 298 K for the reaction of formaldehyde (CH2O) with hydrogen gas using the following inform
Mariana [72]

Answer:

E. 8.08 x 10⁴.

Explanation:

Hello,

In this case, for the reaction:

CH_2O(g) + 2H_2(g)  \rightleftharpoons CH_4(g) + H_2O(g)

We can compute the Gibbs free energy of reaction via:

\Delta G\°=\Delta H\°-T\Delta S\°

Since both the entropy and enthalpy of reaction are given at 298 K (standard temperature), therefore:

\Delta G\°=-94.9kJ-(298K)(-224.2\frac{J}{K}*\frac{1kJ}{1000kJ} )\\\\\Delta G\°=-28.1kJ

Then, as the equilibrium constant is computed as:

K=exp(-\frac{\Delta G\°}{RT} )

We obtain:

K=exp(-\frac{-28.1kJ/mol}{8.314x10^{-3}\frac{kJ}{mol* K}}*298K )\\\\K=8.08 x10^4

For which the answer is E. 8.08 x 10⁴.

Best regards,

3 0
4 years ago
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