Answer:
12. 1 second, 35 ft; 2 seconds, 32 ft
13. (t, y) = (1.4 seconds, 37.6 feet)
14. 37.6 ft; the vertex is the highest point
Step-by-step explanation:
12. You have properly answered question 12.
After 1 second, the height is 35 feet; after 2 seconds, it is 32 feet.
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13. My method of choice is to plot the graph on a graphing calculator and let it show me the coordinates of the vertex when I highlight that point. (See attached.) The vertex is ...
(t, y) = (1.4, 37.6)
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14. The graph is a graph of height when the object is launched with a vertical velocity of 45 ft/s. So, the maximum of the graph will correspond to the maximum height of the object. The vertex is that maximum point, and its y-coordinate is that maximum height.
The maximum height is 37.6 feet.
There are three terms in alg exp
We are given:

Our goal in solving for any variable, in this case is x, we need to isolate x on one side of the variable. Let's start by subtracting 7x from both sides, which will cancel the +7x on the right side. We are then left with:

Now, we want to move that +10 to the other side so our x is all by itself. Let's subtract 10 from both sides, which will cancel the +10 on the right leaving us with:

Since we cannot have a coefficient when solving for x, we need to divide both sides by -3.

When we divide, our answer is:

Add all the numbers of the triangle and then divide them by the sides